Complex Numbers: Operations and the Complex Plane
A complex number has the form where is the real part, is the imaginary part, and .
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- Add / subtract: combine real parts and imaginary parts separately.
- Multiply: FOIL, then replace .
- Conjugate: . To divide, multiply top and bottom by the conjugate of the denominator.
- Complex plane: plot as the point ; the horizontal axis is real (Re), the vertical axis is imaginary (Im).
Simplify . Multiply by the conjugate :
Powers of cycle every 4: . To simplify , divide by and use the remainder.
Modulus, Argument, and Trigonometric (Polar) Form
For :
The trigonometric (polar) form is
where is the modulus and is the argument. To go back to rectangular form, evaluate and .
Write in trig form. Here , so
The point is in Quadrant II, so . Thus
Quadrant check. A calculator's only returns angles in . Always sketch and add (Quadrants II, III) as needed.
Products, Quotients, and DeMoivre's Theorem
Let and .
DeMoivre's Theorem: for any positive integer ,
Compute . First convert: and (Quadrant I), so . By DeMoivre,
Convert back:
Add or subtract from the resulting angle so your final argument is a standard angle in before converting back.
The th Roots of a Complex Number
Every nonzero complex number has exactly distinct th roots:
All roots lie on a circle of radius , equally spaced apart.
Find the three cube roots of . Write , so and the angles are for :
Spacing shortcut. Find the first root (), then add repeatedly to the argument to get the rest.
Polar Coordinates: Points and Conversions
A polar point is located by rotating from the positive -axis, then moving along that ray (if , move backward, i.e. opposite).
Multiple representations: all name the same point.
Distance and midpoint come from the coordinates.
Polar to rectangular: convert .
So . Rectangular to polar: convert .
The point is in Quadrant II, so ; thus .
A polar point is not unique. Adding or flipping the sign of (with a shift) gives another valid name for the same location.
Converting Equations Between Polar and Rectangular Form
Use , , and .
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- Polar Rect: multiply through by to create , , or , then substitute.
- Rect Polar: replace ; solve for . Useful: , , so a vertical line becomes and a horizontal line becomes .
Polar to rectangular: convert . Multiply by : , so
a circle centered at with radius . Rectangular to polar: convert . Substitute : , so .
The circle passes through the origin with center ; the circle has center . Both have radius .
Graphs of Polar Equations
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- Circle: (center origin), or (through origin).
- Cardioid: or (heart shape; ).
- Lima con: or . Ratio : inner loop, cardioid, dimpled, convex.
- Rose: or . Petal length ; odd petals, even petals.
- Lemniscate: or (figure-eight).
Rose petal count trap: the number of petals depends on the parity of , not on itself. has petals; has petals; has petals.
Going Deeper: Advanced Polar & Complex Ideas
The th roots of unity are the solutions of . Writing , they are the equally spaced points
Two identities fall out of the geometry:
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- Sum is zero: for (finite geometric series with ratio and ). The roots balance about the origin.
- Product identity: . (Factor , divide by , then let .)
Solve . Here and , so and the arguments are for . All five roots:
They sit at the vertices of a regular pentagon on the unit circle. Their sum pairs conjugates:
confirming .
If lies on the unit circle then . By DeMoivre, and , so adding and subtracting gives
The special case is the workhorse: raising it to a power and expanding lets you rewrite as a sum of terms (Fourier/power-reduction identities).
Expand two ways. By DeMoivre it equals . By the binomial theorem (writing ),
Matching real and imaginary parts:
using (and ) to simplify.
Treat as the point and read as the distance from to the point .
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- is a circle of radius centered at .
- is the perpendicular bisector of the segment .
- with is the Apollonius circle: the set of points whose distances to and are in a fixed ratio .
To find it, square both sides and expand with ; the and terms survive with equal coefficients, so the result is always a circle.
Square: , i.e. . Multiply by :
Expand: . The terms cancel, leaving
a circle of radius centered at the origin (drawn above).
Sum of the roots of . The equation has no term, so by Vieta's formulas the roots always sum to (for ), and their product is . Geometrically the roots are points equally spaced on a circle of radius , so their centroid is the origin.
A thin wedge of angle at radius is a circular sector of area . Summing wedges, the area swept by from to is
Choosing limits: for one rose petal, integrate between the two consecutive where ; for a full cardioid, use to once around. For the area between two curves, subtract: .
Area of one petal of . A petal runs from to (where ):
using . Intersection of and . Set the radii equal:
giving : the points and . Also check the pole separately: the cardioid reaches at and the circle reaches at , so both pass through the origin even though no single solves the equation there.
Polar intersection trap. Setting can miss intersections, because the same point has many names . Always test the pole and try replacing with or in one equation before solving.
Formulas, Proofs & Tips
What it means. A complex number is a length and a direction; powering it powers the length and multiplies the angle.
Example. : here , , so and , giving .
Why it works. Multiplying two complex numbers in polar form and applying the sine and cosine sum formulas produces with angle — multiplication adds angles. Repeating times gives De Moivre.
Tip. and — but check the quadrant, since only returns two of them.