Parabolas: Focus, Directrix, and Latus Rectum
A parabola is the set of points equidistant from a fixed focus and a fixed line, the directrix. The number is the signed distance from vertex to focus.
- Vertical axis: focus , directrix . Opens up if , down if .
- Horizontal axis: focus , directrix . Opens right if , left if .
- Latus rectum (focal chord through the focus, perpendicular to the axis) has length .
- Eccentricity of every parabola is .
Put the vertex at the origin, the focus at and the directrix at . A point is equally far from both when ; squaring and cancelling leaves . So is not a stretch factor chosen for convenience: it is the actual distance from the vertex to the focus.
Group the squared variable and complete the square:
So ; vertex ; opens up. Focus ; directrix ; latus rectum .
Eliminating the parameter and forgetting the restrictions it carried. , traces the circle once per ; , is only the right half of the sideways parabola… actually all of it, but would be only part.
Horizontal axis, vertex . , opens right. Focus ; directrix ; latus rectum .
Tip: The squared variable tells you the axis. If is squared, the parabola opens up/down; if is squared, it opens left/right. The focus always sits inside the curve, the directrix outside.
For , give the vertex, focus, directrix, direction of opening, and latus rectum length.
Work it on paper before revealing the answer.
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Answer: Vertex ; ; focus ; directrix ; opens up; latus rectum .
Ellipses: Center, Axes, Foci, Eccentricity
- = semi-major axis (largest denominator, ); = semi-minor axis.
- Vertices are from center along the major axis; co-vertices are from center along the minor axis.
- Foci lie on the major axis, from center, where .
- Eccentricity , with (nearer is more circular).
An ellipse is the set of points whose distances to two foci add to the same total, . At the end of the minor axis the two distances are equal, each , and they form a right triangle with legs and ; that triangle is the relation . The closer the foci sit to the centre (small ), the rounder the ellipse, which is what measures.
Group by variable, factor out leading coefficients, then complete each square:
Center ; so ; major axis horizontal. . Vertices ; co-vertices ; foci ; .
Tip: The larger denominator is always , and it names the direction of the major axis: under means horizontal, under means vertical. Add the amounts you completed to both sides, remembering to multiply by the factored-out coefficient.
For , give the vertices, co-vertices, foci and eccentricity.
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Answer: vertices , co-vertices , foci , . , , and .
Hyperbolas: Vertices, Foci, Asymptotes, Eccentricity
- The positive term names the transverse axis; is its denominator (it need not be the larger one).
- Vertices are from center along the transverse axis; foci are from center with .
- Asymptotes: for the left/right form; for the up/down form.
- Eccentricity , with .
Watch the sign on the group when factoring out :
Center ; so ; opens left/right. . Vertices ; foci ; asymptotes ; .
Tip: For a hyperbola is the largest of the three ( and ) because . Do not assume : for a hyperbola is simply whichever denominator sits under the positive term.
For , give the vertices, foci, asymptotes and eccentricity.
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Answer: vertices , foci , asymptotes , . For a hyperbola .
Classifying Conics from the General Form
With no term, classifies by comparing and :
- Circle: (and same sign), e.g. .
- Parabola: exactly one of is (only one variable is squared).
- Ellipse: and have the same sign but .
- Hyperbola: and have opposite signs ().
- : circle.
- : only is squared parabola.
- : same sign, ellipse.
- : opposite signs hyperbola.
Tip: Classify before completing the square. The sign comparison of and instantly names the conic; completing the square then locates its center and features.
Classify: (a) ; (b) ; (c) .
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Answer: (a) hyperbola (, opposite signs); (b) circle (); (c) parabola (only is squared).
Parametric Equations
A parametric curve gives and each as a function of a third variable :
As increases the point traces the curve in a definite direction (its orientation).
- Graph by a table: choose values of , compute , and connect in order of increasing .
- Eliminate the parameter: solve one equation for (or use a trig identity) and substitute to get a relation in and .
A parametrization is a record of motion: is the clock and is where the point is at that moment. Eliminating keeps the path but throws away the timing, which is why two different parametrizations can trace the same curve at different speeds or in opposite directions.
From the second equation . Substitute: . The curve is a sideways parabola opening right, traced upward as increases. Building a table:
Solve for the trig functions: and . Apply :
This is an ellipse with , traced counterclockwise.
To parametrize the line segment from to for , use
At you are at ; at at .
Tip: For trig parametrizations reach for the identity (or for hyperbolas) rather than solving for . Always state the direction and any restriction on the resulting graph.
Eliminate the parameter: , . Describe the curve and its direction.
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Answer: , a parabola with vertex , traced left to right as increases. From the first equation ; substitute into the second.
Polar Equations of Conics (Introduction)
With a focus at the pole, a conic has polar equation
where is the eccentricity and is the distance from focus to directrix.
- parabola, ellipse, hyperbola.
- means the directrix is vertical; means it is horizontal.
Put the constant term to by dividing numerator and denominator by :
So : an ellipse. From and we get ; the directrix is vertical.
Tip: Before reading off , force the denominator into the form by dividing through by the leading constant. Only then is the coefficient of or equal to .
Identify and locate its directrix.
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Answer: a parabola; directrix . Divide by : , so and , giving . The puts the directrix below the pole.
Where Conics Come From: Slicing a Cone
Take a DOUBLE cone (two ice-cream cones tip to tip, extending forever) and cut it with a plane. The angle of the cut decides everything: a horizontal cut gives a circle; tilt the plane a little and the circle stretches into an ellipse.
Tilt the plane until it is exactly PARALLEL to the cone's slant side and the curve never closes up — that single borderline angle produces the parabola. It is the knife-edge between the closed curves (ellipses) and the doubly-open one (hyperbola).
Tilt past the parallel position (or cut straight down) and the plane slices BOTH halves of the double cone, producing the two branches of a hyperbola. The two branches are one curve — the same plane meeting the same cone, twice.
Circle, ellipse, parabola, hyperbola are not four unrelated graphs — they are the SAME construction (plane meets cone) at four tilts. That is why their equations are all degree-two: covers every one of them.
Match each eccentricity to its conic: , , , .
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Answer: circle, ellipse, parabola, hyperbola. Eccentricity measures how far the cutting plane tilts from horizontal: is the flat cut, is the cut parallel to the side, and beyond the plane catches both nappes.
The Ellipse
Standard form (with ): the long semi-axis is , the short one , and the two foci sit at with . The defining property: every point of the ellipse has distances to the two foci summing to (a loop of string around two pins traces one).
, , so and the foci are . Check the string property at : distances and sum to ✓. Eccentricity measures how stretched it is ( is a circle).
An ellipse has vertices and foci . Write its equation.
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Answer: . and , so .
The Parabola
: focus , directrix , and every point of the curve is EQUIDISTANT from the focus and the directrix. Satellite dishes are parabolas because incoming parallel rays all bounce to the focus.
Rewrite as : , so — focus , directrix . The point : distance to focus , distance to directrix ✓.
The Hyperbola
opens left-right with foci at , (note the PLUS — foci sit outside), and asymptotes : the branches hug these lines forever without touching. Defining property: the DIFFERENCE of the focal distances is constant ().
, : , foci , asymptotes . At the vertex the focal distances are and : difference ✓.
Going Deeper: Advanced Conics & Parametrics
Substitute a line into a conic and collect a quadratic in . The line is tangent exactly when that quadratic has a double root, i.e. its discriminant is (secant if the discriminant is positive, misses if negative). Carrying this out once gives memorable tangency conditions for lines of slope :
- Ellipse : tangent iff .
- Hyperbola : tangent iff .
- Parabola : tangent iff (line ).
These same relations let you find a conic from tangency, point, or focus data: each condition gives one equation in the unknowns , and you solve the resulting system.
Here . The tangency condition gives
So the two tangent lines of slope are and . (Check: substituting either into the ellipse yields a perfect-square quadratic in .)
Find the ellipse centered at the origin with horizontal major axis, a focus at , that is tangent to the line .
Adding and subtracting: . The ellipse is . Since , the foci are indeed , confirming the fit.
Reflection property (why conics focus light and sound):
- Parabola: rays traveling parallel to the axis reflect through the focus (and vice versa) — the principle behind satellite dishes and headlights.
- Ellipse: a ray leaving one focus reflects to the other focus — “whispering galleries.”
- Hyperbola: a ray aimed at one focus reflects away from the other focus.
A focal chord is any chord through a focus. The latus rectum is the focal chord perpendicular to the major/transverse axis; its half-length (the semi-latus rectum) controls the polar form below.
For an ellipse and for a hyperbola , so knowing and recovers the full shape. Every focal chord of a conic has semi-latus rectum as its harmonic-mean radius.
The full second-degree equation
may include a cross term , which rotates the axes. The rotation-invariant discriminant classifies the curve without ever finding the rotation angle:
- ellipse (circle if also ),
- parabola,
- hyperbola.
When this reduces to the earlier sign test on and . Shortest distance to a conic: the closest point of a smooth conic to an external line lies where a tangent is parallel to that line, so slide the tangency condition to the tangent line nearest the given one, then measure the gap between the two parallel lines.
- : here , so hyperbola (rotated ).
- : ellipse.
- : parabola.
Find the shortest distance from the line to the ellipse . The line has slope . The parallel tangents satisfy , so ; the one nearer the line is , i.e. . The gap between the parallel lines and is
Consider for . Rather than solving for , combine the equations: and , so their product removes :
This is a hyperbola with . Because satisfies , only the outer branches are traced: gives the right branch, the left. The same trick with uses to yield .
Polar eccentricity form, revisited: in the numerator is the semi-latus rectum , so once you normalize the denominator to you can read off both (the coefficient) and (the numerator), then recover for an ellipse or for a hyperbola. Pitfalls: always normalize the leading denominator constant to before reading ; when a cross term is present, classify with (not the -vs- test); and for rational or trig parametrizations always state the branch or orientation restriction the algebra hides.
Why It Works
Why does a parabolic mirror focus light? For the tangent at makes equal angles with the vertical (incoming) ray and the line to the focus — a computation with the slope and the reflection law. So every vertical ray reflects through the focus. The ellipse's foci have the analogous property, which is why whispering galleries work: sound from one focus reflects to the other.
Do not read a proof the way you read a rule. Cover the last line, ask what the previous line forces, and only then uncover it. If a step feels like magic, that is the step to work by hand with a concrete number.
Formulas, Proofs & Tips
What it means. All points at distance from the centre .
Example. Center , radius : .
Why it works. A circle is by definition the set of points a fixed distance from the centre. Writing that distance with the distance formula gives ; squaring both sides removes the root.
Tip. Given , complete the square in and in to recover the centre and radius.