Long Division

Study Sheet

Long Division

Quotients and remainders

Sharing What Is Left

Concept
The Big Idea

Divide as far as you can in whole groups. Whatever cannot be shared is the remainder, and it is always smaller than the divisor.

Division asks how many equal groups you can make. Long division does that one place value at a time: how many hundreds, then how many tens, then how many ones, subtracting what you have used at each step. Whatever is left at the end is the remainder, and it must be smaller than the divisor — otherwise you could have made one more group.

Tip
The check

Always: divisor×quotient+remainder=the original number\text{divisor} \times \text{quotient} + \text{remainder} = \text{the original number}. If that fails, something went wrong.

Example
Finding 47÷547 \div 5
Nine groups of 5 use 45 dots; the 2 open dots are the remainder.

5×9=455 \times 9 = 45, and 47−45=247 - 45 = 2. So the quotient is 99 remainder 22. Check: 5×9+2=475 \times 9 + 2 = 47.

Example
Finding 29÷429 \div 4
048121620242832123456729
Seven jumps of 4 reach 28; the last step, from 28 to 29, is the remainder 1.

Count up in fours until the next step would pass 2929: 4,8,12,16,20,24,284, 8, 12, 16, 20, 24, 28. That is 77 fours, and one more would be 3232, too big. 29−28=129 - 28 = 1 is left. So 29÷4=729 \div 4 = 7 remainder 11. Check: 4×7+1=294 \times 7 + 1 = 29.

Side note
Where it goes wrong

A remainder that is bigger than the divisor. If you are dividing by 66 and see a remainder of 88, one more group of 66 fits — go back and add 11 to that digit of the quotient.

Try it
Try it: 38÷738 \div 7

Find 38÷738 \div 7. Write the quotient and the remainder, then check.

Show the answer

7×5=357 \times 5 = 35, and 7×6=427 \times 6 = 42 is too big, so the quotient is 55. Left over: 38−35=338 - 35 = 3. Answer: 5\mathbf{5} remainder 3\mathbf{3}. Check: 7×5+3=387 \times 5 + 3 = 38, and 3<73 < 7.

In Plain Terms & More Examples

Concept
In plain terms

Share into equal groups as far as you can; whatever is left over is the remainder, and it is always smaller than the number you divided by.

Example
Finding 58÷658 \div 6

6×9=546 \times 9 = 54, and 58−54=458 - 54 = 4. So 99 remainder 44. Check: 6×9+4=586 \times 9 + 4 = 58.

Example
Finding 73÷873 \div 8
Nine groups of 8 use 72; one dot is left over.

8×9=728 \times 9 = 72, and 73−72=173 - 72 = 1. So 99 remainder 11. Check: 8×9+1=738 \times 9 + 1 = 73.

Side note
Where it goes wrong

Choosing a quotient that is too small. For 58÷658 \div 6 someone writes 88 remainder 1010, because 6×8=486 \times 8 = 48 and 58−48=1058 - 48 = 10. The check even works (6×8+10=586 \times 8 + 10 = 58), but a remainder of 1010 still holds another group of 66. Take it out: 99 remainder 44.

Try it
Try it: 65÷965 \div 9

Find 65÷965 \div 9, and explain how you know the remainder is small enough.

Show the answer

9×7=639 \times 7 = 63, and 9×8=729 \times 8 = 72 is too big, so the quotient is 77 and the remainder is 65−63=265 - 63 = 2: the answer is 7\mathbf{7} remainder 2\mathbf{2}. The remainder 22 is less than 99, so no more groups of 99 fit.

Dividing Three-Digit Numbers

Concept
Place by place

Ask how many times the divisor fits into the hundreds, then bring down the tens, then the ones. Each answer digit goes above the digit you just used.

Long division shares out the biggest pieces first. Think of 372372 as 33 hundreds, 77 tens and 22 ones, shared among 44. Three hundreds cannot go to 44 people without breaking them, so trade them for 3030 tens: now there are 3737 tens. Each share gets 99 tens (3636 of them), and the 11 ten left over is traded for 1010 ones. With the 22 ones that makes 1212 ones, so each share also gets 33 ones. Every "bring down" is one of these trades.

Example
Finding 372÷4372 \div 4
36−4 × 9 = 361212−4 × 3 = 120372493
Each small note is the multiplication behind a step; the dashed arrows bring down the next digit.

44 into 33: does not fit, so use 3737. 4×9=364\times9 = 36, remainder 11; bring down the 22 to make 1212; 4×3=124\times3 = 12, remainder 00. Quotient 93\mathbf{93}. Check: 4×93=3724\times93 = 372.

Example
Finding 652÷3652 \div 3
6−3 × 2 = 653−3 × 1 = 32221−3 × 7 = 2116523217R 1
Three steps, one for each digit of 652.

66 hundreds ÷3\div 3 is 22 each, with nothing left. Bring down the 55: 5÷3=15 \div 3 = 1, remainder 22. Bring down the 22 to make 2222: 22÷3=722 \div 3 = 7, remainder 11. Quotient 217217 remainder 11. Check: 3×217+1=651+1=6523 \times 217 + 1 = 651 + 1 = 652.

Tip
Zero in the middle

If a step gives 00, WRITE the 00 in the quotient. 618÷6=103618 \div 6 = 103, not 1313.

Side note
Where it goes wrong
8−4 × 2 = 820−4 × 0 = 02424−4 × 6 = 2408244206
The 0 in the quotient holds the tens place.

Skipping the zero. In 824÷4824 \div 4: 8÷4=28 \div 4 = 2. Bring down the 22: 2÷42 \div 4 is 00 — easy to forget — and then 24÷4=624 \div 4 = 6. Without the 00 the answer reads 2626, but 4×26=1044 \times 26 = 104, nowhere near 824824. With the zero written, the answer is 206206, and 4×206=8244 \times 206 = 824.

Try it
Try it: 845÷5845 \div 5

Work place by place and check by multiplying back.

Show the answer

55 into 88 is 11 remainder 33; 34÷5=634 \div 5 = 6 remainder 44; 45÷5=945 \div 5 = 9. Quotient 169\mathbf{169}. Check: 5×169=8455\times169 = 845.

Word Problems

Concept
What the remainder means

After dividing, ask what the remainder is in the story. Sometimes it means one more is needed (another bus). Sometimes it is thrown away (a scrap too short to use). Sometimes it is the answer (the leftovers).

The arithmetic is the same every time; only the question changes. 150÷12=12150 \div 12 = 12 remainder 66 says twelve full cartons and six loose eggs. If the question is "how many cartons are full?", the answer is 1212. If it is "how many cartons carry every egg?", it is 1313. If it is "how many eggs are loose?", it is 66.

Example
Packing eggs

150150 eggs are packed in cartons of 1212. 150÷12=12150 \div 12 = 12 remainder 66: twelve full cartons and 66 eggs left over — so 1313 cartons are needed to carry them all.

Example
Sharing stickers
8−4 × 2 = 81512−4 × 3 = 12395423R 3
95 ÷ 4 = 23 R 3.

9595 stickers are shared equally among 44 friends. How many does each get, and how many are left? 4×23=924 \times 23 = 92, so 95÷4=2395 \div 4 = 23 remainder 33. Each friend gets 2323 stickers. Here the remainder answers the second question: 33 stickers are left over.

Side note
Where it goes wrong
8888882 cm scrap
Six 8 cm pieces use 48 cm; the shaded 2 cm is too short for a seventh.

Rounding up when the leftover is useless. A 5050 cm ribbon is cut into 88 cm pieces: 50÷8=650 \div 8 = 6 remainder 22. The answer is 66 pieces, not 77: the 22 cm scrap cannot make another 88 cm piece. Round up only when the leftover still needs something, like students who still need a seat.

Try it
Try it: buses

A school needs to move 263263 students on buses that hold 4040. How many buses are needed?

Show the answer

263÷40=6263 \div 40 = 6 remainder 2323. Six buses carry 240240; the remaining 2323 students need a seventh bus: 7\mathbf{7} buses. (The remainder means "one more", not "ignore it".)

Partial Quotients

Concept
Take away easy groups

Division asks how many groups of the divisor fit. You do not have to find the answer in one go: take away easy chunks such as 1010 or 100100 groups, keep count of how many groups you took, and add up the counts at the end.

This works because division is repeated subtraction: 156÷6156 \div 6 asks how many 66s can be taken away from 156156. Taking them ten at a time is faster than one at a time, and the total count comes out the same. The area model shows it too: a rectangle of area 156156 with one side 66 is built from strips, and the strip widths add up to the missing side.

Example
Finding 156÷6156 \div 6
601060103666
Area 156 with one side 6: the other side is 10 + 10 + 6 = 26.

Take 1010 groups of 66: 156−60=96156 - 60 = 96. Take 1010 more: 96−60=3696 - 60 = 36. Take 66 groups: 36−36=036 - 36 = 0. Groups taken: 10+10+6=2610 + 10 + 6 = 26. So 156÷6=26156 \div 6 = 26. Check: 6×26=1566 \times 26 = 156.

Example
Finding 1,248÷41{,}248 \div 4
120030048124
Two strips: 4 × 300 = 1200 and 4 × 12 = 48.

Take 300300 groups of 44: 1,248−1,200=481{,}248 - 1{,}200 = 48. Take 1212 groups: 48−48=048 - 48 = 0. Groups: 300+12=312300 + 12 = 312. Check: 4×312=1,2484 \times 312 = 1{,}248.

Example
Finding 437÷5437 \div 5

Take 8080 groups of 55: 437−400=37437 - 400 = 37. Take 77 groups: 37−35=237 - 35 = 2. Only 22 is left, less than 55, so stop. Groups: 80+7=8780 + 7 = 87, remainder 22. Check: 5×87+2=4375 \times 87 + 2 = 437.

Side note
Where it goes wrong

Taking a chunk that is too big. For 156÷6156 \div 6, taking 3030 groups means subtracting 6×30=1806 \times 30 = 180, which is more than 156156: you cannot take away more than you have. Pick a chunk no bigger than what is left. Small chunks are slower but never wrong.

Try it
Try it: 912÷8912 \div 8

Use partial quotients. Start with 100100 groups of 88.

Show the answer

912−800=112912 - 800 = 112 (100100 groups). 112−80=32112 - 80 = 32 (1010 groups). 32−32=032 - 32 = 0 (44 groups). Total: 100+10+4=114100 + 10 + 4 = \mathbf{114}. Check: 8×114=9128 \times 114 = 912.

Why It Works

Every division fits one equation: dividend=divisor×quotient+remainder\text{dividend} = \text{divisor}\times\text{quotient} + \text{remainder}, with 0≤remainder<divisor0 \le \text{remainder} < \text{divisor}. That is why you can always check: for 95÷495 \div 4 we get 2323 remainder 33, and 4×23+3=954\times23 + 3 = 95 ✓. The step-by-step subtraction is just this equation being built one place value at a time, and the check works for every division you will ever do.

Tip
Reading a proof

Do not read a proof the way you read a rule. Cover the last line, ask what the previous line forces, and only then uncover it. If a step feels like magic, that is the step to work by hand with a concrete number.