Core Ideas in Plain Terms

Study Sheet

Core Ideas in Plain Terms

Shapes and reasoning, in everyday language

Angles and Lines

Concept
Angles in a shape add to a fixed total

The Triangle Angle-Sum Theorem says the three angles of any triangle add to 180∘180^\circ; a quadrilateral adds to 360∘360^\circ — both come from the polygon angle-sum formula (n−2)⋅180∘(n-2) \cdot 180^\circ. So a missing angle is just the total minus the ones you know. When a line crosses two parallel lines, it makes matching (equal) angles — the key to "angle chasing."

Example
Find the third angle
50°60°?
50∘^\circ + 60∘^\circ + ? = 180∘^\circ.

A triangle has angles 50∘50^\circ and 60∘60^\circ; by the Triangle Angle-Sum Theorem the third is 180∘−110∘=70∘180^\circ - 110^\circ = 70^\circ.

Triangles and the Pythagorean Theorem

Concept
Right triangles: a² + b² = c²

In a right triangle, the two short sides (legs) and the longest side (hypotenuse) satisfy the Pythagorean theorem: a2+b2=c2a^2 + b^2 = c^2. A few side-triples come up constantly — 3-4-53\text{-}4\text{-}5, 5-12-135\text{-}12\text{-}13 — so recognizing them saves time.

Reminder — The Pythagorean theorem:  a2+b2=c2a^2+b^2=c^2
Example
Find the hypotenuse
43c
The 3-4-5 right triangle.

Legs 33 and 44: by the Pythagorean theorem, c=32+42=25=5c = \sqrt{3^2 + 4^2} = \sqrt{25} = 5.

Similarity, Area, and Volume

Concept
Same shape, scaled size

Two figures are similar if one is a scaled copy of the other — all angles equal, all sides in the same ratio. If you scale lengths by kk, areas scale by k2k^2 and volumes by k3k^3. That is why doubling a shape's size quadruples its area.

Example
Area of a triangle
64
The triangle fills exactly half of the 6 by 4 rectangle around it.

Using the triangle-area formula A=12bhA = \tfrac12 bh: base 66, height 44 gives A=12⋅6⋅4=12A = \tfrac12 \cdot 6 \cdot 4 = 12.

Going Deeper: Circles and Coordinates

Concept
Inscribed angles are half the central angle

An angle drawn from the circle's edge sees an arc at half the angle drawn from the center. Two consequences worth knowing cold: every inscribed angle in a semicircle is 90∘90^\circ, and inscribed angles on the same arc are equal.

Example
Use it
40°AB
Arc AB is 80∘^\circ; every inscribed angle standing on it is 40∘^\circ.

If arc ABAB measures 80∘80^\circ, an inscribed angle standing on ABAB measures 40∘40^\circ — no matter where on the far side of the circle its vertex sits.

Concept
Distance and midpoint are Pythagoras in disguise
xy−1123−11234345
From (0, 0) to (3, 4): legs 3 and 4, distance 5.

The distance between two points is (Δx)2+(Δy)2\sqrt{(\Delta x)^2 + (\Delta y)^2} — the hypotenuse of the right triangle their coordinates make. From (0,0)(0,0) to (3,4)(3,4): 9+16=5\sqrt{9+16} = 5. The midpoint just averages the coordinates.

Example
Power of a Point (multi-step)
ABCDP463
PD is found from 4 ⋅\cdot 6 = 3 ⋅\cdot PD.

Chords ABAB and CDCD meet at PP inside a circle, with AP=4AP = 4, PB=6PB = 6, and CP=3CP = 3. The Power of a Point theorem says AP⋅PB=CP⋅PDAP \cdot PB = CP \cdot PD. Step 1: AP⋅PB=4⋅6=24AP \cdot PB = 4 \cdot 6 = 24. Step 2: PD=24÷3=8PD = 24 \div 3 = 8.

Example
Ptolemy's theorem (multi-step)
7242015ABCD
Drawn to scale: the diagonal BD measures 20.

Quadrilateral ABCDABCD is inscribed in a circle with diagonal AC=25AC = 25 a diameter, and sides AB=7AB = 7, BC=24BC = 24, CD=20CD = 20, DA=15DA = 15. Ptolemy's theorem says AC⋅BD=AB⋅CD+AD⋅BCAC \cdot BD = AB \cdot CD + AD \cdot BC. Step 1: 7⋅20+15⋅24=140+360=5007 \cdot 20 + 15 \cdot 24 = 140 + 360 = 500. Step 2: BD=500÷25=20BD = 500 \div 25 = 20.

Problem-Solving Playbook

Concept
Add a line

When a figure gives you nothing to compute with, add an auxiliary line: a radius to a tangent point, an altitude, a diagonal. Each new line creates triangles — and triangles bring the Pythagorean theorem, similarity, and area formulas into play.

Example
Worked: Heron's formula
141315
Sides 13, 14, 15 and no height given.

A triangle has sides 1313, 1414, 1515. Heron's formula: with s=13+14+152=21s = \dfrac{13+14+15}{2} = 21, the area is s(s−a)(s−b)(s−c)=21⋅8⋅7⋅6=7056=84\sqrt{s(s-a)(s-b)(s-c)} = \sqrt{21 \cdot 8 \cdot 7 \cdot 6} = \sqrt{7056} = 84.