Three Forms of a Quadratic
Every quadratic function can be written in three equivalent forms. Each form reveals something different at a glance.
- Standard form: (reveals the -intercept )
- Vertex form: (reveals the vertex )
- Factored form: (reveals the -intercepts )
In all three, the number is the same: it controls direction and width.
Vertex form shows the vertex directly; completing the square converts to it. When the discriminant is negative the roots are complex: and numbers obey ordinary algebra with that one extra fact. Complex roots of real quadratics come in conjugate pairs.
Each form is built to answer one question with no work. Standard form gives at once. Vertex form shows the smallest (or largest) value, because the square is never negative and is zero only at . Factored form is zero exactly when a factor is zero, so it shows the roots. All three are the same function, which is why converting between them never changes the graph.
Consider (standard). Its vertex is at , giving , so
Factoring the standard form: , so
Simplifying as . Convert first: . The product rule for roots needs non-negative radicands.
Tip: To go from standard to vertex form, complete the square. To go from standard to factored form, factor (or use the roots from the quadratic formula). To go back to standard from either, expand and combine like terms.
Write in vertex form and in factored form. Name the vertex, the roots and the -intercept.
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Vertex form: , vertex . Factored: , roots and . -intercept . Check: the axis is halfway between the roots.
Graphing Parabolas
For :
- Direction: opens up if (has a minimum), down if (has a maximum).
- Axis of symmetry: the vertical line .
- Vertex: ; this is the min or max point.
- -intercept: . -intercepts: solve .
Every parabola is the graph of moved and stretched. The sign of flips it or not, the size of narrows or widens it, and the vertex locates it; the axis of symmetry follows because takes the same value at and , so after shifting, points equally far left and right of have equal heights.
For : so it opens down with a maximum. The axis of symmetry is and the vertex is .
Plotting only the vertex and the intercepts and then guessing the width. Use symmetry: for , the point gives for free, and gives .
Transformations of : shifts the graph right , up , and stretches by (reflects if ). Bigger means a narrower parabola.
For , give the direction, vertex, axis, -intercept and -intercepts.
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Opens up (). Vertex , axis . . Roots: , , so or , symmetric about .
Solving by Factoring and the Square-Root Method
Factoring uses the Zero Product Property: if then or . Set the quadratic equal to , factor, and solve each factor.
Square-root method works when there is no middle () term, or when one side is a perfect square: isolate the square, then take the square root of both sides.
Both methods exploit a special shape. A product is zero only when a factor is zero, so factored form hands you the roots. A square equals exactly when the thing being squared is or , so isolating a square reduces the equation to two linear ones. On the graph, the line meets at two points, units either side of the axis.
Solve . Factor: , so or .
Expanding first when the square is already isolated: turned into works, but taking roots directly is two lines. The reverse mistake is worse: taking the root of an unisolated square, .
Solve . Take roots: , so or .
Remember the ! A square root gives two solutions. Dropping the negative root loses half your answers.
Solve and .
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First: , so or (do not divide by , which loses ). Second: , , , so or .
Completing the Square
To complete the square on , add . This makes
Use this to solve any quadratic or to convert to vertex form.
Picture as an -by- square with a -by- strip. Split the strip into two -by- pieces along two sides of the square and a -by- corner is missing. Adding fills it, and the whole shape is the square . Completing the square turns any quadratic into vertex form, which is why it both solves equations and locates vertices.
Solve .
Completing the square without factoring out : with "" added, giving , which is not a perfect square. Factor first: . The added inside counts as outside.
Write in vertex form. Take :
Tip: If , factor out of the and terms first, then complete the square inside the parentheses.
Write in vertex form and give the maximum value.
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Factor from the first two terms: . Add and subtract inside: . Opens down, so the maximum value is , at .
The Quadratic Formula and the Discriminant
For with ,
The quantity under the radical, , is the discriminant:
- : two distinct real solutions.
- : one repeated real solution.
- : two complex (nonreal) solutions.
The formula is completing the square done once on (see Why It Works). Read it as a location plus a spread: the roots sit at , the axis of symmetry, plus or minus . When that spread is imaginary, which is exactly the complex case.
Solve , so .
So or . (Here : two real roots.)
Writing as when . With , . Always substitute with parentheses: and .
Check first: compute the discriminant before solving. It tells you how many and what kind of answers to expect.
Solve with the formula. What does say about the graph?
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: two real roots, so the graph crosses the -axis twice. , about and .
Complex Numbers: the Imaginary Unit
The imaginary unit is defined by , so that . A complex number has standard form , where is the real part and is the imaginary part.
Powers of cycle with period :
Real numbers cannot solve , because every real square is non-negative. The number is introduced to be that solution, and every arithmetic law is kept. The powers of cycle because ; on the complex plane, multiplying by is a quarter turn, so four multiplications bring you back to the start.
. .
Computing from the exponent's last digit or by "so ." Use the remainder: , so .
Powers of : divide the exponent by and keep the remainder: remainder , , , .
Simplify , , and .
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, so . . .
Operations with Complex Numbers
Add/subtract: combine real parts and imaginary parts separately.
Multiply: use FOIL, then replace with .
Conjugate: the conjugate of is . Their product is a real number.
Divide: multiply numerator and denominator by the conjugate of the denominator.
Complex numbers follow the same algebra as polynomials in , with one extra rule, . That is why multiplication is FOIL and why the conjugate helps with division: , a real number, so multiplying top and bottom by the conjugate clears from the denominator just as rationalizing clears a radical.
Leaving in the answer or replacing it with : , then "." Since , , and the product is .
Tip: A complex answer is not finished until it is in the form . Real and imaginary parts should be separated.
For and , find , , and .
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. . . .
Quadratics with Complex Solutions
If the discriminant , the graph has no -intercepts and the two solutions are complex conjugates . Solve exactly as before—the negative under the radical just introduces .
The complex roots still carry the geometry. In , the real part is the axis of symmetry, exactly where real roots would have been centered. The imaginary part measures how far the parabola would have to drop to touch the axis: in vertex form , setting it to gives , so .
Solve , so .
The solutions are and , a conjugate pair.
Stopping at "no solution" when . There is no real solution, but there are two complex ones; read the question to see which it asks for. has solutions .
Remember: complex roots always come in conjugate pairs and (for real coefficients).
Solve .
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, and . So . The real part is the axis of symmetry.
Modeling with Quadratics
Quadratics model projectile height, areas, and any quantity with a single maximum or minimum.
- Projectiles: (feet, seconds). The peak is at the vertex time ; the ground is where .
- Max/min: the extreme value always occurs at the vertex.
Quadratic models appear whenever a rate of change itself changes at a steady rate. Gravity slows a rising ball by ft/s every second, so its height gains shrink steadily and the height graph bends into a parabola. The same shape appears in area problems, because a rectangle's area is a product of two quantities that each change linearly.
A ball is thrown so . Vertex time: s. Max height ft. It lands when , at s.
Answering "how high?" with the vertex time. is when the ball is highest; the height is ft.
Tip: “When is it highest?” asks for the vertex time; “how high?” asks for the vertex -value; “when does it land?” asks for the positive root.
A theater sells tickets at ; each increase loses sales. What price maximizes revenue?
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At price , sales are , so . Vertex at : price , tickets, revenue .
Going Deeper: Advanced Quadratics & Complex Numbers
For with roots , dividing by gives . Comparing with shows
These Vieta's formulas let you read the sum and product of the roots straight off the coefficients—no solving required. Any symmetric function of the roots can then be rebuilt from these two numbers, e.g.
Without solving, evaluate and for .
First read off the symmetric quantities with :
Now assemble the answers from these:
Test for a symmetric expression: if swapping leaves it unchanged, it can be written using only and . Start every such problem by writing down those two values.
To construct a monic quadratic with prescribed roots , use
When the new roots are transformations of old roots , compute the new sum and product from Vieta's formulas of the original equation—you never need the roots themselves.
- Roots : replace by in the original.
- Roots : new sum , new product .
- Roots : reverse the coefficient list .
The equation has roots . Build a quadratic whose roots are and .
From Vieta: and . The new sum and product are
So a quadratic with these roots is
Treat the discriminant as a function of an unknown parameter to force a desired root behavior:
- Two distinct real roots: .
- One repeated (double) root: .
- No real roots (complex pair): .
Setting also gives the tangency condition when a line meets a parabola in exactly one point (see below), and the boundary value where the number of real roots changes.
Watch the leading coefficient. If the parameter multiplies , first insist (otherwise the equation is linear, not quadratic) before applying a discriminant condition.
For which value of is the line tangent to the parabola ?
Tangency means the system meets in exactly one point, so set the two expressions equal and require a double root:
A double root needs :
Both lines touch the parabola at a single point.
Plot as the point . Its modulus (distance from the origin) and argument (angle from the positive real axis) are
Key facts: , moduli multiply (), and multiplying by rotates a point counterclockwise. This geometric view explains why the powers of cycle: has modulus and argument , so walks around the unit circle in steps.
Find the modulus and argument of .
because sits in the second quadrant. So has modulus and argument .
Find every complex with .
Take moduli of both sides: , so . Hence or .
- If then , which checks: .
- If , multiply by : . So is a cube root of unity.
The cube roots of unity are and . Together with these are the four solutions:
Conjugate root pairs. A polynomial with real coefficients has complex roots only in conjugate pairs: if is a root, so is . That pair multiplies back to the real quadratic factor
whose sum of roots and product are exactly Vieta's formulas again.
Why It Works
The quadratic formula gives roots ; when , and the two roots differ only in the sign of the -part — they are conjugates. Conjugates make the algebra close up: is real, which is why dividing complex numbers works by multiplying by the conjugate, and why a real polynomial's non-real roots always pair off.
Do not read a proof the way you read a rule. Cover the last line, ask what the previous line forces, and only then uncover it. If a step feels like magic, that is the step to work by hand with a concrete number.
Formulas, Proofs & Tips (1 of 2)
What it means. Solves every quadratic , factorable or not.
Example. : , so or .
Why it works. Complete the square. Divide by : . Add to both sides so the left is a perfect square: . Take square roots and subtract .
Tip. Write the equation as first — every term must be on one side, or your will be wrong.
What it means. The part under the root. : two real roots. : one repeated root. : two complex roots.
Example. has , so one repeated real root.
Why it works. In the quadratic formula the roots differ by . A positive gives two distinct real shifts, zero gives none, and a negative forces the square root to be imaginary.
Tip. If is a perfect square the quadratic factors over the integers — worth checking before reaching for the formula.
What it means. The turning point — the minimum if , the maximum if .
Example. : vertex at , , so .
Why it works. The two roots of the quadratic formula sit symmetrically either side of , so that value is the axis of symmetry. A parabola turns exactly on its axis of symmetry.
Tip. This also gives the max/min value of a quadratic without calculus — useful for word problems about greatest area or lowest cost.
What it means. is the number whose square is ; complex numbers multiply like binomials, using at the end.
Example. .
Why it works. Expand and replace by , which turns into and collects into real and imaginary parts.
Tip. To divide, multiply top and bottom by the conjugate : is real, clearing from the denominator.
Formulas, Proofs & Tips (2 of 2)
What it means. The sum and product of a quadratic's roots read straight off its coefficients.
Example. : the roots sum to and multiply to , so they are and .
Why it works. If are the roots then . Matching coefficients gives both formulas.
Tip. Great for "find the sum of the roots" questions — you never have to solve the equation.