Course Review

Study Sheet

Course Review

Every key definition, rule, and formula across all 11 topics

Equations, Inequalities & Absolute Value

Concept
Core Moves

Equations: isolate the variable by undoing operations in reverse order --- distribute, clear fractions with the LCD, gather variable terms on one side, divide by the coefficient. Keep every step equivalent.

Literal equations: same moves, but treat the other letters as constants. If the target variable appears in two terms, factor it out first: ax+bx=cx=ca+bax+bx=c \Rightarrow x=\dfrac{c}{a+b}.

Inequalities: solve like equations, but flip the sign when you multiply or divide by a negative.

Absolute value: x|x| is distance from 00 (never negative). Isolate |\cdot| first, then split.

  • [leftmargin=*,itemsep=1pt]
  • ax+b=c (c>0)|ax+b|=c\ (c>0): ax+b=cax+b=c or ax+b=cax+b=-c.
  • ax+b<c|ax+b|<c: “less thAND” c<ax+b<c-c<ax+b<c.
  • ax+b>c|ax+b|>c: “greatOR” ax+b<cax+b<-c or ax+b>cax+b>c.
Concept
Interval Notation

multicols2

  • [leftmargin=*,itemsep=1pt]
  • x<ax<a: (,a)(-\infty,\,a)
  • xax\le a: (,a](-\infty,\,a]
  • x>ax>a: (a,)(a,\,\infty)
  • xax\ge a: [a,)[a,\,\infty)
  • AND: a<x<b(a,b)a<x<b \to (a,b)
  • OR: (,a)(b,)(-\infty,a)\cup(b,\infty)

multicols Use a parenthesis next to ±\pm\infty --- infinity is never included.

Example
Worked Example: Absolute-Value OR Inequality

Solve 2x+1>5|2x+1|>5.

2x+1<5or2x+1>52x+1<-5 \quad\text{or}\quad 2x+1>5
x<3orx>2.x<-3 \qquad\text{or}\qquad x>2.

Interval notation: (,3)(2,)(-\infty,\,-3)\cup(2,\,\infty).

Tip

Special cases. No solution: 6=76=7 (contradiction), or x<2|x|<-2. All reals: 6=66=6 (identity), or x>2|x|>-2.

Functions, Relations & Transformations

Concept
Functions & Domain/Range

A relation pairs inputs with outputs; a function assigns exactly one output to each input (passes the vertical line test). Domain = allowed inputs xx; range = resulting outputs yy.

  • [leftmargin=*,itemsep=1pt]
  • Exclude xx that make a denominator zero.
  • Exclude xx that make an even radicand negative (need radicand 0\ge 0).
Concept
Parent Functions

multicols2

  • [leftmargin=*,itemsep=1pt]
  • Linear: y=xy=x
  • Quadratic: y=x2y=x^2
  • Cubic: y=x3y=x^3
  • Absolute value: y=xy=|x|
  • Square root: y=xy=\sqrt{x}
  • Reciprocal: y=1xy=\tfrac{1}{x}
  • Exponential: y=bxy=b^x
  • Logarithmic: y=logbxy=\log_b x

multicols

Concept
Transformations of y=af(b(xh))+ky=a\,f\big(b(x-h)\big)+k
  • [leftmargin=*,itemsep=1pt]
  • hh: horizontal shift (right if h>0h>0);   kk: vertical shift (up if k>0k>0).
  • a>1|a|>1 vertical stretch, 0<a<10<|a|<1 vertical shrink; a<0a<0 reflects over the xx-axis.
  • bb affects horizontal scaling by factor 1b\tfrac{1}{|b|}; b<0b<0 reflects over the yy-axis.

Composition: (fg)(x)=f(g(x))(f\circ g)(x)=f\big(g(x)\big) --- do gg first (inside out).

Inverse f1f^{-1}: swap xx and yy, then solve for yy. Graphs reflect over y=xy=x; a one-to-one function (horizontal line test) has an inverse. Check: f(f1(x))=xf\big(f^{-1}(x)\big)=x.

Example
Worked Example: Composition & Inverse

Let f(x)=2x3f(x)=2x-3.   (ff)(x)=2(2x3)3=4x9(f\circ f)(x)=2(2x-3)-3=4x-9.

Inverse: y=2x3x=2y3y=x+32y=2x-3 \Rightarrow x=2y-3 \Rightarrow y=\dfrac{x+3}{2}, so f1(x)=x+32f^{-1}(x)=\dfrac{x+3}{2}.

Tip

Order inside the parentheses matters. f(x2)+5f(x-2)+5 shifts right 22 (inside, opposite sign) and up 55. Horizontal moves are counterintuitive; vertical moves are literal.

Linear Systems & Matrices

Concept
Solving Systems
  • [leftmargin=*,itemsep=1pt]
  • Substitution: solve one equation for a variable, substitute.
  • Elimination: add multiples of equations to cancel a variable.
  • 3-variable: eliminate one variable twice to reduce to a 2×22\times2 system, then back-substitute.

Outcomes: one solution (lines cross), no solution (parallel, 0=k0=k), infinitely many (same line, 0=00=0).

Concept
Matrix Operations

Add/subtract entrywise (same dimensions). Scalar cc: multiply every entry.

Multiplication ABAB: needs (columns of AA) == (rows of BB); entry == row \cdot column dot product. Not commutative.

[abcd][efgh]=[ae+bgaf+bhce+dgcf+dh]\begin{bmatrix} a & b\\ c & d \end{bmatrix} \begin{bmatrix} e & f\\ g & h \end{bmatrix} = \begin{bmatrix} ae+bg & af+bh\\ ce+dg & cf+dh \end{bmatrix}
Concept
Determinants, Inverse & Cramer's Rule

2×22\times2: det[abcd]=adbc\det\begin{bmatrix} a & b\\ c & d \end{bmatrix}=ad-bc.   Inverse: A1=1adbc[dbca]A^{-1}=\dfrac{1}{ad-bc}\begin{bmatrix} d & -b\\ -c & a \end{bmatrix} (exists iff det0\det\ne 0).

Cramer's Rule for {ax+by=ecx+dy=f\begin{cases} ax+by=e\\ cx+dy=f \end{cases} with D=adbc0D=ad-bc\ne0:

x=det[ebfd]D,y=det[aecf]D.x=\frac{\det\begin{bmatrix} e & b\\ f & d \end{bmatrix}}{D},\qquad y=\frac{\det\begin{bmatrix} a & e\\ c & f \end{bmatrix}}{D}.

Replace the variable's column with the constants.

Example
Worked Example: Cramer's Rule

Solve {2x+3y=8xy=1\begin{cases} 2x+3y=8\\ x-y=1 \end{cases}. D=2(1)3(1)=5D=2(-1)-3(1)=-5.

x=(8)(1)(3)(1)5=115=115,y=(2)(1)(8)(1)5=65=65.x=\frac{(8)(-1)-(3)(1)}{-5}=\frac{-11}{-5}=\tfrac{11}{5},\qquad y=\frac{(2)(1)-(8)(1)}{-5}=\frac{-6}{-5}=\tfrac{6}{5}.
Tip

If det=0\det=0, there is no unique solution (parallel or coincident) and no inverse exists. Cramer's Rule cannot be used.

Quadratic Functions & Complex Numbers

Concept
Three Forms of a Quadratic
  • [leftmargin=*,itemsep=1pt]
  • Standard: y=ax2+bx+cy=ax^2+bx+c; vertex at x=b2ax=-\dfrac{b}{2a}; yy-intercept (0,c)(0,c).
  • Vertex: y=a(xh)2+ky=a(x-h)^2+k; vertex (h,k)(h,k); axis x=hx=h.
  • Factored: y=a(xr1)(xr2)y=a(x-r_1)(x-r_2); zeros r1,r2r_1,r_2.

Opens up if a>0a>0, down if a<0a<0.

Concept
Solving Methods & Discriminant

multicols2

  • [leftmargin=*,itemsep=1pt]
  • Factoring / Zero Product
  • Square roots
  • Completing the square
  • Quadratic formula

multicols

x=b±b24ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Discriminant D=b24acD=b^2-4ac: D>0D>0 two real roots; D=0D=0 one repeated real root; D<0D<0 two complex conjugate roots.

Reminder — The quadratic formula:x=b±b24ac2a(a0)x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\qquad (a\neq 0)
Concept
Complex Numbers

i=1i=\sqrt{-1}, i2=1i^2=-1. Powers cycle with period 4:

i1=i,i2=1,i3=i,i4=1  (divide exponent by 4, use remainder).i^1=i,\quad i^2=-1,\quad i^3=-i,\quad i^4=1 \ \ (\text{divide exponent by 4, use remainder}).

Add/subtract: combine real and imaginary parts. Multiply: FOIL, replace i2=1i^2=-1. Divide: multiply by the conjugate abia-bi.

(a+bi)(abi)=a2+b2.(a+bi)(a-bi)=a^2+b^2.
Example
Worked Example: Quadratic Formula with Complex Roots

Solve x24x+13=0x^2-4x+13=0. D=1652=36D=16-52=-36.

x=4±362=4±6i2=2±3i.x=\frac{4\pm\sqrt{-36}}{2}=\frac{4\pm 6i}{2}=2\pm 3i.
Tip

Simplify negative radicals before the formula: 36=6i\sqrt{-36}=6i, not ±6\pm6. Complex roots always come in conjugate pairs for real-coefficient equations.

Polynomial Functions

Concept
End Behavior (Leading Term Test)

For degree nn with leading coefficient aa:

  • [leftmargin=*,itemsep=1pt]
  • nn even, a>0a>0: both ends up.   nn even, a<0a<0: both ends down.
  • nn odd, a>0a>0: down-left, up-right.   nn odd, a<0a<0: up-left, down-right.

A degree-nn polynomial has at most nn real zeros and n1n-1 turning points.

Concept
Division & Key Theorems

Synthetic division divides by (xc)(x-c): bring down, multiply by cc, add.

Remainder Theorem: the remainder of P(x)÷(xc)P(x)\div(x-c) equals P(c)P(c).

Factor Theorem: (xc)(x-c) is a factor     P(c)=0\iff P(c)=0.

Rational Root Theorem: any rational zero =pq=\dfrac{p}{q}, where pp\mid (constant term), qq\mid (leading coefficient).

Fundamental Theorem of Algebra: a degree-nn polynomial has exactly nn complex roots (counting multiplicity). Complex and irrational roots come in conjugate pairs.

Example
Worked Example: Synthetic Division

Divide x32x25x+6x^3-2x^2-5x+6 by (x1)(x-1), i.e. c=1c=1:

112561161160\begin{array}{c|cccc} 1 & 1 & -2 & -5 & 6\\ & & 1 & -1 & -6\\ \hline & 1 & -1 & -6 & 0 \end{array}

Quotient x2x6=(x3)(x+2)x^2-x-6=(x-3)(x+2); remainder 00, so zeros are 1,3,21,3,-2.

Tip

A remainder of 00 confirms a factor. Use the depressed quotient to keep factoring until you reach a quadratic you can solve directly.

Rational Expressions & Functions

Concept
Operations
  • [leftmargin=*,itemsep=1pt]
  • Multiply: factor, cancel common factors, multiply across.
  • Divide: multiply by the reciprocal.
  • Add/subtract: get a common denominator (LCD), combine numerators.
  • Complex fractions: multiply top and bottom by the overall LCD.

Solving: multiply every term by the LCD to clear fractions, then solve. Check for extraneous roots (any value making a denominator 00 is rejected).

Concept
Asymptotes & Holes

For f(x)=p(x)q(x)f(x)=\dfrac{p(x)}{q(x)} in lowest terms:

  • [leftmargin=*,itemsep=1pt]
  • Vertical asymptote: where q(x)=0q(x)=0 (and p0p\ne0 there).
  • Hole: at a factor that cancels from top and bottom.
  • Horizontal asymptote: compare degrees --- deg top << bottom: y=0y=0; equal: y=leadleady=\dfrac{\text{lead}}{\text{lead}}; top >> bottom by 1: slant asymptote (by division).
Concept
Variation
  • [leftmargin=*,itemsep=1pt]
  • Direct: y=kxy=kx.   Inverse: y=kxy=\dfrac{k}{x}.
  • Joint: y=kxzy=kxz.   Combined: y=kxzy=\dfrac{kx}{z}.

Find kk from a known data point, then answer the question.

Example
Worked Example: Solve a Rational Equation

Solve 3x+12=5x\dfrac{3}{x}+\dfrac{1}{2}=\dfrac{5}{x}. LCD =2x=2x.

2x3x+2x12=2x5x  6+x=10  x=4.2x\cdot\frac{3}{x}+2x\cdot\frac{1}{2}=2x\cdot\frac{5}{x}\ \Rightarrow\ 6+x=10\ \Rightarrow\ x=4.

x=4x=4 does not make any denominator 00, so it is valid.

Tip

Always factor first. Cancel only common factors, never individual terms across ++ or -. Discard solutions that zero a denominator.

Radical Functions & Rational Exponents

Concept
nnth Roots & Rational Exponents

an=a1/n\sqrt[n]{a}=a^{1/n},   am/n=amn=(an)ma^{m/n}=\sqrt[n]{a^m}=\big(\sqrt[n]{a}\big)^m.

Even index: radicand must be 0\ge 0; principal root is nonnegative. Odd index: any real radicand.

Exponent rules still apply: multicols2

  • [leftmargin=*,itemsep=1pt]
  • aman=am+na^m a^n=a^{m+n}
  • aman=amn\dfrac{a^m}{a^n}=a^{m-n}
  • (am)n=amn(a^m)^n=a^{mn}
  • an=1ana^{-n}=\dfrac{1}{a^n}

multicols

Concept
Radical Equations & Inverses

Solve: isolate the radical, raise both sides to the index power, solve, then check for extraneous roots (squaring can introduce false solutions).

The inverse of y=x2y=x^2 (x0x\ge0) is y=xy=\sqrt{x}; more generally squaring and square-rooting undo each other on the appropriate domain.

Example
Worked Example: Radical Equation

Solve 2x+3=x\sqrt{2x+3}=x.

2x+3=x2  x22x3=0  (x3)(x+1)=0.2x+3=x^2 \ \Rightarrow\ x^2-2x-3=0 \ \Rightarrow\ (x-3)(x+1)=0.

x=3x=3 or x=1x=-1. Check: 9=3\sqrt{9}=3 ✓; 1=11\sqrt{1}=1\ne-1 (extraneous). Solution: x=3x=3.

Tip

Isolate before you power. With two radicals, isolate one, square, isolate the remaining radical, square again. Always check answers in the original equation.

Exponential & Logarithmic Functions

Concept
Definitions

y=bxy=b^x (b>0, b1b>0,\ b\ne1): growth if b>1b>1, decay if 0<b<10<b<1; horizontal asymptote y=0y=0. The number e2.71828e\approx 2.71828.

Logarithm is the inverse: logby=x    bx=y\log_b y=x \iff b^x=y.   lnx=logex\ln x=\log_e x.   logx=log10x\log x=\log_{10}x.

logb1=0,logbb=1,blogbx=x.\log_b 1=0,\qquad \log_b b=1,\qquad b^{\log_b x}=x.
Concept
Log Properties & Change of Base

multicols2

  • [leftmargin=*,itemsep=1pt]
  • Product: logb(MN)=logbM+logbN\log_b(MN)=\log_b M+\log_b N
  • Quotient: logb ⁣MN=logbMlogbN\log_b\!\dfrac{M}{N}=\log_b M-\log_b N
  • Power: logb(Mp)=plogbM\log_b(M^p)=p\log_b M
  • Change of base: logbx=lnxlnb\log_b x=\dfrac{\ln x}{\ln b}

multicols Solving: exponential equations --- take a log of both sides (or equate bases). Log equations --- rewrite in exponential form, then check the domain (arguments must be >0>0).

Concept
Growth, Decay & Interest

multicols2

  • [leftmargin=*,itemsep=1pt]
  • General: A=A0(1±r)tA=A_0(1\pm r)^t
  • Continuous: A=A0ertA=A_0 e^{rt}
  • Compound: A=P(1+rn)ntA=P\Big(1+\dfrac{r}{n}\Big)^{nt}
  • Continuous interest: A=PertA=Pe^{rt}

multicols Here rr = rate (decimal), nn = compounds per year, tt = years.

Example
Worked Example: Solve an Exponential Equation

Solve 3x=203^{x}=20.

x=log320=ln20ln32.9961.0992.73.x=\log_3 20=\frac{\ln 20}{\ln 3}\approx\frac{2.996}{1.099}\approx 2.73.
Tip

Condense before solving log equations: use the properties to write a single log, convert to exponential form, then reject any solution that makes an argument 0\le 0.

Sequences & Series

Concept
Arithmetic (common difference dd)
an=a1+(n1)d,Sn=n2(a1+an)=n2(2a1+(n1)d).a_n=a_1+(n-1)d,\qquad S_n=\frac{n}{2}\big(a_1+a_n\big)=\frac{n}{2}\big(2a_1+(n-1)d\big).

Add a constant dd each term.

Concept
Geometric (common ratio rr)
an=a1rn1,Sn=a11rn1r (r1).a_n=a_1 r^{\,n-1},\qquad S_n=a_1\frac{1-r^{\,n}}{1-r}\ (r\ne1).

Infinite geometric sum converges only when r<1|r|<1:

S=a11r.S_\infty=\frac{a_1}{1-r}.

Multiply by a constant rr each term.

Concept
Sigma (Summation) Notation
k=1nak=a1+a2++an.\sum_{k=1}^{n} a_k = a_1+a_2+\cdots+a_n.

kk is the index, the bottom value is the start, the top value is the end. Useful facts:

k=1nc=cn,k=1nk=n(n+1)2.\sum_{k=1}^{n} c=cn,\qquad \sum_{k=1}^{n} k=\frac{n(n+1)}{2}.
Example
Worked Example: Infinite Geometric Series

Evaluate 8+4+2+1+8+4+2+1+\cdots. Here a1=8a_1=8, r=12r=\tfrac12, r<1|r|<1:

S=8112=812=16.S_\infty=\frac{8}{1-\tfrac12}=\frac{8}{\tfrac12}=16.
Tip

Identify the type first. Constant difference \to arithmetic; constant ratio \to geometric. An infinite geometric series diverges (no finite sum) when r1|r|\ge 1.

Conic Sections

Concept
Circle & Parabola

Circle: center (h,k)(h,k), radius rr:

(xh)2+(yk)2=r2.(x-h)^2+(y-k)^2=r^2.

Parabola (vertex (h,k)(h,k), pp = vertex-to-focus distance):

  • [leftmargin=*,itemsep=1pt]
  • Opens up/down: (xh)2=4p(yk)(x-h)^2=4p(y-k); focus (h,k+p)(h,k+p), directrix y=kpy=k-p.
  • Opens left/right: (yk)2=4p(xh)(y-k)^2=4p(x-h); focus (h+p,k)(h+p,k), directrix x=hpx=h-p.
Concept
Ellipse & Hyperbola (center (h,k)(h,k))

Ellipse (a>ba>b, aa = semi-major): (xh)2a2+(yk)2b2=1\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1, foci on major axis with c2=a2b2c^2=a^2-b^2.

Hyperbola: (xh)2a2(yk)2b2=1\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1 (opens left/right), with c2=a2+b2c^2=a^2+b^2 and asymptotes yk=±ba(xh)y-k=\pm\dfrac{b}{a}(x-h).

Eccentricity e=cae=\dfrac{c}{a}: circle e=0e=0; ellipse 0<e<10<e<1; parabola e=1e=1; hyperbola e>1e>1.

Concept
Identifying a Conic from Ax2+Cy2+=0Ax^2+Cy^2+\cdots=0
  • [leftmargin=*,itemsep=1pt]
  • Only one squared term \to parabola.
  • A=CA=C (same sign) \to circle.
  • ACA\ne C, same sign \to ellipse.
  • Opposite signs \to hyperbola.
Example
Worked Example: Complete the Square (Circle)

Write x2+y26x+4y3=0x^2+y^2-6x+4y-3=0 in standard form.

(x26x+9)+(y2+4y+4)=3+9+4(x^2-6x+9)+(y^2+4y+4)=3+9+4
(x3)2+(y+2)2=16.(x-3)^2+(y+2)^2=16.

Center (3,2)(3,-2), radius 44.

Tip

Ellipse vs. hyperbola hinges on the sign between terms: a ++ gives an ellipse, a - gives a hyperbola. For an ellipse c2=a2b2c^2=a^2-b^2; for a hyperbola c2=a2+b2c^2=a^2+b^2.

Probability & Statistics

Concept
Counting: Permutations & Combinations

Fundamental Counting Principle: multiply the choices at each stage.

nPr=n!(nr)!  (order matters),nCr=(nr)=n!r!(nr)!  (order does not).{}_nP_r=\frac{n!}{(n-r)!}\ \ (\text{order matters}),\qquad {}_nC_r=\binom{n}{r}=\frac{n!}{r!\,(n-r)!}\ \ (\text{order does not}).
Concept
Probability Rules

P(E)=favorabletotalP(E)=\dfrac{\text{favorable}}{\text{total}}, with 0P(E)10\le P(E)\le1; complement P(E)=1P(E)P(E')=1-P(E).

  • [leftmargin=*,itemsep=1pt]
  • Addition: P(A or B)=P(A)+P(B)P(A and B)P(A\text{ or }B)=P(A)+P(B)-P(A\text{ and }B) (subtract 00 if mutually exclusive).
  • Multiplication (independent): P(A and B)=P(A)P(B)P(A\text{ and }B)=P(A)\cdot P(B).
  • Conditional: P(BA)=P(A and B)P(A)P(B\mid A)=\dfrac{P(A\text{ and }B)}{P(A)}.
Concept
Binomial Probability

For nn independent trials, success probability pp, exactly kk successes:

P(k)=(nk)pk(1p)nk.P(k)=\binom{n}{k}p^{k}(1-p)^{\,n-k}.
Concept
Mean, Standard Deviation & the Normal Curve
mean xˉ=xn,standard deviation σ=(xxˉ)2n.\text{mean}\ \bar{x}=\frac{\sum x}{n},\qquad \text{standard deviation}\ \sigma=\sqrt{\frac{\sum (x-\bar{x})^2}{n}}.

Empirical (68--95--99.7) Rule for a normal distribution: about 68%68\% of data lie within 1σ1\sigma of the mean, 95%95\% within 2σ2\sigma, 99.7%99.7\% within 3σ3\sigma.

zz-score: z=xxˉσz=\dfrac{x-\bar{x}}{\sigma} (number of standard deviations from the mean).

Example
Worked Example: Empirical Rule

Test scores are normal with xˉ=70\bar{x}=70, σ=8\sigma=8. What percent scored between 6262 and 8686?

62=701σ62=70-1\sigma and 86=70+2σ86=70+2\sigma. From the mean out to 1σ-1\sigma is 34%34\%; from the mean out to +2σ+2\sigma is 47.5%47.5\%. Total =34%+47.5%=81.5%=34\%+47.5\%=81.5\%.

Tip

Order matters \to permutation; order doesn't \to combination. “And” usually means multiply, “or” means add (subtract the overlap when events can happen together).