Polynomials

Study Sheet

Polynomials

Vocabulary, degree, standard form, adding, subtracting, multiplying, and special products

What Is a Polynomial?

Concept
The Building Blocks

A term is a number, a variable, or a number multiplied by variables raised to whole-number powers. Examples of terms: 77, 3x3x, 5x2-5x^2, x3x^3.

A polynomial is a sum of terms. In each term:

  • [leftmargin=*]
  • the coefficient is the number multiplied by the variable (in 5x2-5x^2 the coefficient is 5-5);
  • a constant is a term with no variable (like 22 in 3x25x+23x^2-5x+2).
Concept
Naming Polynomials by the Number of Terms
  • [leftmargin=*]
  • Monomial — one term: 4x34x^3
  • Binomial — two terms: x+3x+3
  • Trinomial — three terms: 3x25x+23x^2-5x+2
  • Polynomial — the general word for one or more terms (four or more terms usually just get called “a polynomial”).
Example
Example: Identify the parts of 3x25x+23x^2-5x+2

This is a trinomial (three terms).

  • [leftmargin=*]
  • Terms: 3x23x^2, 5x-5x, 22
  • Coefficients: 33 (of x2x^2) and 5-5 (of xx)
  • Constant: 22
Tip

Watch the sign! The term 5x-5x has a negative coefficient. Always carry the sign in front of a term along with the term.

Degree, Leading Coefficient, and Standard Form

Concept
Degree

The degree of a term is the exponent on its variable (5x3-5x^3 has degree 33; a constant like 7=7x07=7x^0 has degree 00).

The degree of a polynomial is the largest degree among its terms.

Concept
Standard Form and Leading Coefficient

A polynomial is in standard form when its terms are written in descending order of degree (highest power first).

The leading coefficient is the coefficient of the first term once the polynomial is in standard form (the coefficient of the highest-degree term).

Example
Example: Put 47x+2x34-7x+2x^3 in standard form

Order the terms from highest power to lowest:

2x37x+4.2x^3 - 7x + 4.
  • [leftmargin=*]
  • Degree of the polynomial: 33
  • Leading coefficient: 22
  • Constant: 44
Example
Example: Degree and leading coefficient of 6x2x5+46x^2-x^5+4

Standard form: x5+6x2+4-x^5+6x^2+4.

  • [leftmargin=*]
  • Degree: 55
  • Leading coefficient: 1-1 (the coefficient of x5-x^5)
Tip

Tip: A missing power is fine---x5+6x2+4-x^5+6x^2+4 simply has no x4x^4, x3x^3, or x1x^1 terms. Standard form only cares about ordering the terms that are there.

Evaluating a Polynomial

Concept
Substitute and Simplify

To evaluate a polynomial for a given value, replace every variable with that value (use parentheses!), then follow the order of operations.

Example
Example: Evaluate 2x25x+12x^2-5x+1 at x=3x=3
2(3)25(3)+1=2(9)15+1=1815+1=4.\begin{aligned} 2(3)^2 - 5(3) + 1 &= 2(9) - 15 + 1 \\ &= 18 - 15 + 1 \\ &= 4. \end{aligned}
Example
Example: Evaluate x2+4x-x^2+4x at x=2x=-2
(2)2+4(2)=(4)8=48=12.\begin{aligned} -(-2)^2 + 4(-2) &= -(4) - 8 \\ &= -4 - 8 = -12. \end{aligned}
Tip

Careful with negatives: (2)2-(-2)^2 means “take the opposite of (2)2(-2)^2.” Square first: (2)2=4(-2)^2=4; then apply the minus: 4-4. Always wrap the substituted value in parentheses.

Adding Polynomials

Concept
Combine Like Terms

Like terms have the exact same variable part (same variable, same exponent), such as 3x23x^2 and 5x25x^2. To add polynomials, drop the parentheses and combine like terms.

Example
Example: (4x23x+1)+(x2+3x5)(4x^2-3x+1)+(x^2+3x-5)

Group like terms, then add:

(4x2+x2)+(3x+3x)+(15)=5x2+0x4=5x24.\begin{aligned} (4x^2+x^2) + (-3x+3x) + (1-5) &= 5x^2 + 0x - 4 \\ &= 5x^2 - 4. \end{aligned}
Tip

Only like terms combine. You cannot add 5x25x^2 and 4-4 into one term---different powers stay separate. The answer 5x245x^2-4 is fully simplified.

Subtracting Polynomials

Concept
Distribute the Negative

To subtract, distribute the minus sign to every term of the second polynomial (this flips each sign), and then combine like terms.

Example
Example: (6x2+2x1)(3x2x+4)(6x^2+2x-1)-(3x^2-x+4)

Distribute the negative across the second group:

6x2+2x1    3x2+x4=(6x23x2)+(2x+x)+(14)=3x2+3x5.\begin{aligned} 6x^2+2x-1 \;-\; 3x^2 + x - 4 &= (6x^2-3x^2) + (2x+x) + (-1-4) \\ &= 3x^2 + 3x - 5. \end{aligned}
Tip

The most common mistake! Subtracting (3x2x+4)(3x^2-x+4) changes all three signs: 3x2-3x^2, +x+x, 4-4. It is easy to flip only the first term---flip them all.

Multiplying a Monomial by a Polynomial

Concept
The Distributive Property

Multiply the monomial by each term inside the parentheses. Multiply the coefficients, and add the exponents on matching variables (xaxb=xa+bx^a\cdot x^b=x^{a+b}).

Example
Example: 4x(x22x+1)-4x(x^2-2x+1)

Distribute 4x-4x to each term:

4xx2    4x(2x)    4x1=4x3+8x24x.\begin{aligned} -4x\cdot x^2 \;-\; 4x\cdot(-2x) \;-\; 4x\cdot 1 &= -4x^3 + 8x^2 - 4x. \end{aligned}
Tip

Exponent reminder: xx2=x1+2=x3x\cdot x^2 = x^{1+2}=x^3. Add exponents when multiplying powers of the same base---do not multiply them.

Multiplying Two Binomials (FOIL)

Concept
FOIL

FOIL names the four products you make when multiplying two binomials:

FFirstOOuterIInnerLLast\underbrace{\text{F}}_{\text{First}}\quad \underbrace{\text{O}}_{\text{Outer}}\quad \underbrace{\text{I}}_{\text{Inner}}\quad \underbrace{\text{L}}_{\text{Last}}

Then combine the two middle (Outer ++ Inner) like terms.

Example
Example: (x+4)(x1)(x+4)(x-1)
First: xx=x2Outer: x(1)=xInner: 4x=4xLast: 4(1)=4Add: x2x+4x4=x2+3x4.\begin{aligned} \text{First: } & x\cdot x = x^2 \\ \text{Outer: } & x\cdot(-1) = -x \\ \text{Inner: } & 4\cdot x = 4x \\ \text{Last: } & 4\cdot(-1) = -4 \\[2pt] \text{Add: } & x^2 - x + 4x - 4 = x^2 + 3x - 4. \end{aligned}
Example
Example with coefficients: (3x4)(2x+5)(3x-4)(2x+5)
F: 3x2x=6x2O: 3x5=15xI: 42x=8xL: 45=206x2+15x8x20=6x2+7x20.\begin{aligned} \text{F: } & 3x\cdot 2x = 6x^2 \\ \text{O: } & 3x\cdot 5 = 15x \\ \text{I: } & -4\cdot 2x = -8x \\ \text{L: } & -4\cdot 5 = -20 \\[2pt] & 6x^2 + 15x - 8x - 20 = 6x^2 + 7x - 20. \end{aligned}
Tip

FOIL is just the distributive property twice. Every term in the first binomial multiplies every term in the second. That idea is what lets us multiply bigger polynomials next.

Multiplying a Binomial by a Trinomial

Concept
Distribute Each Term

Multiply each term of the binomial by each term of the trinomial (that is 2×3=62\times 3 = 6 small products), then combine like terms and write in standard form.

Example
Example: (2x1)(x2+3x5)(2x-1)(x^2+3x-5)

Distribute 2x2x, then distribute 1-1:

2x(x2+3x5)=2x3+6x210x1(x2+3x5)=x23x+5Add: 2x3+(6x2x2)+(10x3x)+5=2x3+5x213x+5.\begin{aligned} 2x(x^2+3x-5) &= 2x^3 + 6x^2 - 10x \\ -1(x^2+3x-5) &= -x^2 - 3x + 5 \\[2pt] \text{Add: } & 2x^3 + (6x^2-x^2) + (-10x-3x) + 5 \\ &= 2x^3 + 5x^2 - 13x + 5. \end{aligned}
Tip

Stay organized. Line up like terms in columns as you go, and count your products---for a binomial times a trinomial you should form exactly six before combining.

Special Products

Concept
Two Patterns Worth Memorizing
Difference of squares:(a+b)(ab)=a2b2Perfect-square trinomial:(a+b)2=a2+2ab+b2(ab)2=a22ab+b2\begin{aligned} \textbf{Difference of squares:}\quad & (a+b)(a-b) = a^2 - b^2 \\ \textbf{Perfect-square trinomial:}\quad & (a+b)^2 = a^2 + 2ab + b^2 \\ & (a-b)^2 = a^2 - 2ab + b^2 \end{aligned}

These come straight from FOIL, but recognizing the pattern saves time.

Example
Difference of squares: (2x+5)(2x5)(2x+5)(2x-5)

Here a=2xa=2x and b=5b=5, so a2b2a^2-b^2:

(2x)2(5)2=4x225.(2x)^2 - (5)^2 = 4x^2 - 25.

Check with FOIL: 4x210x+10x25=4x2254x^2 - 10x + 10x - 25 = 4x^2 - 25. The middle terms cancel.

Example
Perfect square: (3x4)2(3x-4)^2

Here a=3xa=3x and b=4b=4, so a22ab+b2a^2 - 2ab + b^2:

(3x)22(3x)(4)+(4)2=9x224x+16.\begin{aligned} (3x)^2 - 2(3x)(4) + (4)^2 &= 9x^2 - 24x + 16. \end{aligned}
Tip

Do NOT drop the middle term!(a+b)2a2+b2(a+b)^2 \neq a^2 + b^2.

The correct expansion is (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2. For example, (x+3)2=x2+6x+9(x+3)^2 = x^2 + 6x + 9, not x2+9x^2+9. The 2ab2ab term is the one students forget most often.

Going Deeper: Advanced Polynomials

Concept
The Binomial Theorem

FOIL and repeated distribution get slow for high powers. The Binomial Theorem expands (a+b)n(a+b)^n all at once:

(a+b)n=k=0n(nk)ankbk,(a+b)^n = \sum_{k=0}^{n} \binom{n}{k}\, a^{\,n-k} b^{\,k},

where the binomial coefficient (nk)=n!k!(nk)!\binom{n}{k} = \dfrac{n!}{k!\,(n-k)!} counts the ways to choose kk of the nn factors that contribute a bb.

Reading the pattern for a fixed nn: the power of aa starts at nn and drops by one each term, the power of bb starts at 00 and rises by one, and the two exponents in every term add up to nn.

Reminder — The binomial theorem:(x+y)n=k=0n(nk)xnkyk(x+y)^{n}=\sum_{k=0}^{n}\binom{n}{k}x^{\,n-k}y^{k}
Concept
Pascal's Triangle

The coefficients (nk)\binom{n}{k} are exactly the rows of Pascal's triangle. Each entry is the sum of the two entries above it, and every row begins and ends with 11.

n=0:1n=1:11n=2:121n=3:1331n=4:14641\begin{array}{ccccccccc} n=0: & & & & 1 & & & & \\ n=1: & & & 1 & & 1 & & & \\ n=2: & & 1 & & 2 & & 1 & & \\ n=3: & 1 & & 3 & & 3 & & 1 & \\ n=4: 1 & & 4 & & 6 & & 4 & & 1 \end{array}

So (a+b)4=a4+4a3b+6a2b2+4ab3+b4(a+b)^4 = a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4: the row 1,4,6,4,11,4,6,4,1 becomes the coefficients directly.

Example
Example: Expand (2x+3)3(2x+3)^3 with the Binomial Theorem

Use row n=3n=3 of Pascal's triangle: 1,3,3,11,3,3,1. Take a=2xa=2x, b=3b=3:

(2x+3)3=1(2x)3+3(2x)2(3)+3(2x)(3)2+1(3)3=8x3+3(4x2)(3)+3(2x)(9)+27=8x3+36x2+54x+27.\begin{aligned} (2x+3)^3 &= 1\,(2x)^3 + 3\,(2x)^2(3) + 3\,(2x)(3)^2 + 1\,(3)^3 \\ &= 8x^3 + 3(4x^2)(3) + 3(2x)(9) + 27 \\ &= 8x^3 + 36x^2 + 54x + 27. \end{aligned}
Tip

The coefficient is not just the Pascal number. In (2x+3)3(2x+3)^3 each term also carries the powers of the constants 22 and 33. The Pascal entry 33 became 3636 once (2x)2(2x)^2 and 313^1 were multiplied in. Always raise both pieces of the binomial to their powers.

Concept
Extracting One Coefficient Without Full Expansion

Sometimes you only need a single coefficient of a product. Instead of multiplying everything out, collect only the pairs of terms whose degrees add up to the power you want.

To find the coefficient of xkx^k in a product, list every way to pick one term from each factor so their exponents sum to kk, multiply those coefficients, and add the results.

Example
Example: Coefficient of x2x^2 in (x2+3x4)(2x2x+5)(x^2+3x-4)(2x^2-x+5)

We need every pair of terms whose exponents add to 22:

x25=5x23x(x)=3x242x2=8x2Sum of coefficients: 5+(3)+(8)=6.\begin{aligned} x^2 \cdot 5 &= 5x^2 \\ 3x \cdot (-x) &= -3x^2 \\ -4 \cdot 2x^2 &= -8x^2 \\[2pt] \text{Sum of coefficients: } & 5 + (-3) + (-8) = -6. \end{aligned}

So the coefficient of x2x^2 is 6-6, found without computing any other term.

Concept
Recovering a2+b2a^2+b^2 and a3+b3a^3+b^3 from a+ba+b and abab

The sum a+ba+b and product abab contain enough information to rebuild higher symmetric expressions. Starting from (a+b)2=a2+2ab+b2(a+b)^2 = a^2+2ab+b^2 and (a+b)3=a3+3a2b+3ab2+b3(a+b)^3 = a^3+3a^2b+3ab^2+b^3, rearrange:

a2+b2=(a+b)22ab,a3+b3=(a+b)33ab(a+b).\begin{aligned} a^2+b^2 &= (a+b)^2 - 2ab, \\ a^3+b^3 &= (a+b)^3 - 3ab(a+b). \end{aligned}

The second identity also factors as a3+b3=(a+b)(a2ab+b2)a^3+b^3=(a+b)(a^2-ab+b^2); both give the same value.

Example
Example: If a+b=5a+b=5 and ab=6ab=6, find a2+b2a^2+b^2 and a3+b3a^3+b^3

Substitute directly into the identities:

a2+b2=(a+b)22ab=522(6)=2512=13,a3+b3=(a+b)33ab(a+b)=533(6)(5)=12590=35.\begin{aligned} a^2+b^2 &= (a+b)^2 - 2ab = 5^2 - 2(6) = 25 - 12 = 13, \\ a^3+b^3 &= (a+b)^3 - 3ab(a+b) = 5^3 - 3(6)(5) = 125 - 90 = 35. \end{aligned}

(Check: a=2,b=3a=2,b=3 give a+b=5a+b=5, ab=6ab=6, and indeed 4+9=134+9=13, 8+27=358+27=35.)

Concept
Extending the Special Products: (a+b+c)2(a+b+c)^2

The perfect-square pattern generalizes to three terms. Every term squares, and every distinct pair produces a doubled cross term:

(a+b+c)2=a2+b2+c2+2ab+2ac+2bc.(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc.

There are three squares and three cross terms because there are three ways to pair up aa, bb, and cc.

Tip

Count the cross terms. A common error is writing only a2+b2+c2a^2+b^2+c^2. With nn terms there are nn squares plus one doubled cross term for each pair. For example, (x+2+3y)2=x2+4+9y2+4x+6xy+12y(x+2+3y)^2 = x^2 + 4 + 9y^2 + 4x + 6xy + 12y.

Concept
End Behavior from the Leading Term

For large x|x|, a polynomial behaves like its leading term alone---the highest-degree term dominates every other. So the degree and the sign of the leading coefficient decide the end behavior:

  • [leftmargin=*]
  • Even degree: both ends point the same way---up/up if the leading coefficient is positive, down/down if negative.
  • Odd degree: the ends point opposite ways---down/up if positive, up/down if negative.
Example
Example: End behavior of 2x3+40x27-2x^3 + 40x^2 - 7

Ignore all but the leading term 2x3-2x^3. The degree is odd (33) and the leading coefficient is negative (2-2), so the ends point opposite ways: as x+x\to+\infty the value \to-\infty, and as xx\to-\infty the value +\to+\infty (up on the left, down on the right). The large +40x2+40x^2 term changes the middle shape but never the ends.

Concept
Polynomial Long Division (Preview)

When a polynomial does not divide evenly, long division splits it into a quotient plus a remainder, mirroring long division of numbers. At each step: divide the leading term of the current dividend by the leading term of the divisor, multiply back, and subtract.

Example
Example: Divide x2+5x+7x^2+5x+7 by x+2x+2
x2÷x=x,andx(x+2)=x2+2x,(x2+5x+7)(x2+2x)=3x+7,3x÷x=3,and3(x+2)=3x+6,(3x+7)(3x+6)=1  (remainder).\begin{aligned} x^2 \div x &= x, \quad\text{and}\quad x(x+2) = x^2+2x, \\ (x^2+5x+7) - (x^2+2x) &= 3x+7, \\ 3x \div x &= 3, \quad\text{and}\quad 3(x+2) = 3x+6, \\ (3x+7) - (3x+6) &= 1 \ \ (\text{remainder}). \end{aligned}

So x2+5x+7=(x+2)(x+3)+1x^2+5x+7 = (x+2)(x+3) + 1, i.e. the quotient is x+3x+3 with remainder 11.

Tip

Keep everything in standard form and hold placeholders. Before dividing, order both polynomials by descending degree and insert 00 coefficients for any missing powers (e.g. write x3+1x^3+1 as x3+0x2+0x+1x^3+0x^2+0x+1) so like terms line up during each subtraction.

Formulas, Proofs & Tips

Tip
The distributive property
a(b+c)=ab+aca(b+c)=ab+ac

What it means. Multiplying a sum multiplies each piece of it.

Example. 3(x+2)=3x+63(x+2)=3x+6.

Why it works. a(b+c)a(b+c) is b+cb+c added aa times. Regrouping those copies gives bb added aa times plus cc added aa times, i.e. ab+acab+ac. It is also the area of an a×(b+c)a\times(b+c) rectangle split into two.

Tip. Distribute the sign too: (x4)=x+4-(x-4)=-x+4. Run it backwards to factor.

Tip
Degree and end behaviour
deg(fg)=degf+degg;leading term controls the ends\deg(fg)=\deg f+\deg g;\qquad \text{leading term controls the ends}

What it means. The highest-power term decides what the graph does far left and far right.

Example. 2x3+-2x^3+\cdots rises to the left and falls to the right (odd degree, negative lead).

Why it works. For very large x|x|, xnx^{n} dwarfs every lower power, so the leading term dominates the sum. Multiplying polynomials multiplies their leading terms, adding the exponents.

Tip. Even degree: both ends go the same way. Odd degree: opposite ways. A positive leading coefficient sends the right end up.