Polynomials

Study Sheet

Polynomials

Vocabulary, degree, standard form, adding, subtracting, multiplying, and special products

What Is a Polynomial?

Concept
The Building Blocks

A term is a number, a variable, or a number multiplied by variables raised to whole-number powers. Examples of terms: 77, 3x3x, −5x2-5x^2, x3x^3.

A polynomial is a sum of terms. In each term:

  • the coefficient is the number multiplied by the variable (in −5x2-5x^2 the coefficient is −5-5);
  • a constant is a term with no variable (like 22 in 3x2−5x+23x^2-5x+2).

A polynomial is a sum of terms, each a coefficient times a power of the variable. Adding and subtracting collect like terms; multiplying uses the distributive property on every pair of terms (FOIL is the two-by-two case). The degree is the highest power and it controls the shape and the number of roots.

Polynomials are exactly the expressions built from a variable using only adding, subtracting and multiplying. That is why the exponents must be whole numbers (x−1x^{-1} needs division, x1/2x^{1/2} needs a root), and why polynomials are closed under ++, −- and ×\times: combining two of them never produces anything else.

Concept
Naming Polynomials by the Number of Terms
  • Monomial — one term: 4x34x^3
  • Binomial — two terms: x+3x+3
  • Trinomial — three terms: 3x2−5x+23x^2-5x+2
  • Polynomial — the general word for one or more terms (four or more terms usually just get called “a polynomial”).
Example
Example: Identify the parts of 3x2−5x+23x^2-5x+2

This is a trinomial (three terms).

  • Terms: 3x23x^2, −5x-5x, 22
  • Coefficients: 33 (of x2x^2) and −5-5 (of xx)
  • Constant: 22
Side note
Where it goes wrong

Calling 3x+2\tfrac{3}{x} + 2 a polynomial because it "has terms." 3x=3x−1\tfrac3x = 3x^{-1} has a negative exponent, which requires division by the variable. It is a rational expression, not a polynomial.

Tip

Watch the sign! The term −5x-5x has a negative coefficient. Always carry the sign in front of a term along with the term.

Try it
Try it: polynomial or not?

Which are polynomials: 4x3−12x4x^3 - \tfrac12 x, x+1\sqrt{x} + 1, 77, x2+x−2x^2 + x^{-2}? Name the polynomials by number of terms.

Show the answer

4x3−12x4x^3 - \tfrac12 x is a polynomial (a binomial; fractional coefficients are fine). x+1=x1/2+1\sqrt x + 1 = x^{1/2} + 1 is not. 77 is a polynomial (a monomial of degree 00). x2+x−2x^2 + x^{-2} is not (negative exponent).

Degree, Leading Coefficient, and Standard Form

Concept
Degree

The degree of a term is the exponent on its variable (−5x3-5x^3 has degree 33; a constant like 7=7x07=7x^0 has degree 00).

The degree of a polynomial is the largest degree among its terms.

The degree matters because the highest power eventually outgrows all the others. For 2x3−7x+42x^3 - 7x + 4 at x=10x = 10, the cube contributes 20002000 while the rest contribute −66-66. So the leading term alone predicts the shape far from the origin, and standard form puts it first where you can see it.

Concept
Standard Form and Leading Coefficient

A polynomial is in standard form when its terms are written in descending order of degree (highest power first).

The leading coefficient is the coefficient of the first term once the polynomial is in standard form (the coefficient of the highest-degree term).

Example
Example: Put 4−7x+2x34-7x+2x^3 in standard form
xy−3−2−1123−8−6−4−2246
y=2x3−7x+4y = 2x^3 - 7x + 4: near the origin the −7x-7x matters; far out, 2x32x^3 takes over.

Order the terms from highest power to lowest:

2x3−7x+4.2x^3 - 7x + 4.
  • Degree of the polynomial: 33
  • Leading coefficient: 22
  • Constant: 44
Side note
Where it goes wrong

Reading the leading coefficient from the first term as written: for 6x2−x5+46x^2 - x^5 + 4, "the leading coefficient is 66." Leading means highest degree: the term is −x5-x^5, so the leading coefficient is −1-1.

Example
Example: Degree and leading coefficient of 6x2−x5+46x^2-x^5+4

Standard form: −x5+6x2+4-x^5+6x^2+4.

  • Degree: 55
  • Leading coefficient: −1-1 (the coefficient of −x5-x^5)
Tip

Tip: A missing power is fine—−x5+6x2+4-x^5+6x^2+4 simply has no x4x^4, x3x^3, or x1x^1 terms. Standard form only cares about ordering the terms that are there.

Try it
Try it: standard form

Write 5x−3x4+9+x25x - 3x^4 + 9 + x^2 in standard form; give the degree, leading coefficient and constant term.

Show the answer

Order by degree: −3x4+x2+5x+9-3x^4 + x^2 + 5x + 9. Degree 44, leading coefficient −3-3, constant term 99.

Evaluating a Polynomial

Concept
Substitute and Simplify

To evaluate a polynomial for a given value, replace every variable with that value (use parentheses!), then follow the order of operations.

Evaluating a polynomial at a number gives one point on its graph: the input is the xx-coordinate and the value is the yy-coordinate. That is why parentheses around a substituted negative matter so much; the sign of (−2)2(-2)^2 versus −22-2^2 decides which point you plot.

Example
Example: Evaluate 2x2−5x+12x^2-5x+1 at x=3x=3
xy−1123−3−2−112345(3, 4)
The value 44 at x=3x = 3 is the point (3,4)(3, 4) on the graph.
2(3)2−5(3)+1=2(9)−15+1=18−15+1=4.\begin{aligned} 2(3)^2 - 5(3) + 1 &= 2(9) - 15 + 1 \\ &= 18 - 15 + 1 \\ &= 4. \end{aligned}
Side note
Where it goes wrong

Evaluating −x2-x^2 at x=−2x = -2 as 44. The expression means −(x2)-(x^2): square first, (−2)2=4(-2)^2 = 4, then take the opposite, −4-4.

Example
Example: Evaluate −x2+4x-x^2+4x at x=−2x=-2
−(−2)2+4(−2)=−(4)−8=−4−8=−12.\begin{aligned} -(-2)^2 + 4(-2) &= -(4) - 8 \\ &= -4 - 8 = -12. \end{aligned}
Tip

Careful with negatives: −(−2)2-(-2)^2 means “take the opposite of (−2)2(-2)^2.” Square first: (−2)2=4(-2)^2=4; then apply the minus: −4-4. Always wrap the substituted value in parentheses.

Try it
Try it: evaluate

Evaluate p(x)=x3−4x2+x+6p(x) = x^3 - 4x^2 + x + 6 at x=−1x = -1, 22 and 33.

Show the answer

p(−1)=−1−4−1+6=0p(-1) = -1 - 4 - 1 + 6 = 0. p(2)=8−16+2+6=0p(2) = 8 - 16 + 2 + 6 = 0. p(3)=27−36+3+6=0p(3) = 27 - 36 + 3 + 6 = 0. All three are zeros of pp, points where its graph crosses the xx-axis.

Adding Polynomials

Concept
Combine Like Terms

Like terms have the exact same variable part (same variable, same exponent), such as 3x23x^2 and 5x25x^2. To add polynomials, drop the parentheses and combine like terms.

Adding polynomials is adding like terms, and like terms combine by the distributive property: 4x2+x2=(4+1)x24x^2 + x^2 = (4 + 1)x^2. Aligning terms by degree, the way digits are aligned by place value, keeps the matching visible.

Example
Example: (4x2−3x+1)+(x2+3x−5)(4x^2-3x+1)+(x^2+3x-5)

Group like terms, then add:

(4x2+x2)+(−3x+3x)+(1−5)=5x2+0x−4=5x2−4.\begin{aligned} (4x^2+x^2) + (-3x+3x) + (1-5) &= 5x^2 + 0x - 4 \\ &= 5x^2 - 4. \end{aligned}
Side note
Where it goes wrong

Combining unlike powers: 4x2+3x=7x34x^2 + 3x = 7x^3. Only terms with the same power combine; 4x2+3x4x^2 + 3x is already simplified.

Tip

Only like terms combine. You cannot add 5x25x^2 and −4-4 into one term—different powers stay separate. The answer 5x2−45x^2-4 is fully simplified.

Try it
Try it: add

Add (2x3−5x+7)+(x3+4x2+5x−9)(2x^3 - 5x + 7) + (x^3 + 4x^2 + 5x - 9).

Show the answer

Group by degree: x3x^3: 2+1=32 + 1 = 3; x2x^2: 44; xx: −5+5=0-5 + 5 = 0; constants: 7−9=−27 - 9 = -2. Sum: 3x3+4x2−23x^3 + 4x^2 - 2.

Subtracting Polynomials

Concept
Distribute the Negative

To subtract, distribute the minus sign to every term of the second polynomial (this flips each sign), and then combine like terms.

Subtracting a polynomial is adding its opposite, and the opposite of a sum is the sum of the opposites: −(3x2−x+4)=−3x2+x−4-(3x^2 - x + 4) = -3x^2 + x - 4. That is the distributive property with the factor −1-1, which is why every sign in the second polynomial flips, not only the first.

Example
Example: (6x2+2x−1)−(3x2−x+4)(6x^2+2x-1)-(3x^2-x+4)

Distribute the negative across the second group:

6x2+2x−1  −  3x2+x−4=(6x2−3x2)+(2x+x)+(−1−4)=3x2+3x−5.\begin{aligned} 6x^2+2x-1 \;-\; 3x^2 + x - 4 &= (6x^2-3x^2) + (2x+x) + (-1-4) \\ &= 3x^2 + 3x - 5. \end{aligned}
Side note
Where it goes wrong

Changing only the first sign: (6x2+2x−1)−(3x2−x+4)(6x^2 + 2x - 1) - (3x^2 - x + 4) as 6x2+2x−1−3x2−x+4=3x2+x+36x^2 + 2x - 1 - 3x^2 - x + 4 = 3x^2 + x + 3. Every term flips: −3x2+x−4-3x^2 + x - 4, giving 3x2+3x−53x^2 + 3x - 5.

Tip

The most common mistake! Subtracting (3x2−x+4)(3x^2-x+4) changes all three signs: −3x2-3x^2, +x+x, −4-4. It is easy to flip only the first term—flip them all.

Try it
Try it: subtract

Subtract (5y2−3y−8)−(−2y2+7y−8)(5y^2 - 3y - 8) - (-2y^2 + 7y - 8).

Show the answer

Flip every sign of the second: 5y2−3y−8+2y2−7y+85y^2 - 3y - 8 + 2y^2 - 7y + 8. Combine: 7y2−10y+0=7y2−10y7y^2 - 10y + 0 = 7y^2 - 10y.

Multiplying a Monomial by a Polynomial

Concept
The Distributive Property

Multiply the monomial by each term inside the parentheses. Multiply the coefficients, and add the exponents on matching variables (xa⋅xb=xa+bx^a\cdot x^b=x^{a+b}).

The monomial multiplies each term because of the distributive property, and each little product uses the product rule for exponents: −4x⋅x2=−4x3-4x \cdot x^2 = -4x^3. As an area, it is one rectangle of height −4x-4x cut into pieces of widths x2x^2, −2x-2x and 11.

Example
Example: −4x(x2−2x+1)-4x(x^2-2x+1)
x²−2x1−4x−4x³8x²−4x
One row: −4x-4x times each term.

Distribute −4x-4x to each term:

−4x⋅x2  −  4x⋅(−2x)  −  4x⋅1=−4x3+8x2−4x.\begin{aligned} -4x\cdot x^2 \;-\; 4x\cdot(-2x) \;-\; 4x\cdot 1 &= -4x^3 + 8x^2 - 4x. \end{aligned}
Side note
Where it goes wrong

Forgetting to multiply the exponents' bases: 3x2(2x3)=6x63x^2(2x^3) = 6x^6 ("multiply everything"). Coefficients multiply (3⋅2=63 \cdot 2 = 6) but exponents add: x2+3=x5x^{2 + 3} = x^5, so 6x56x^5.

Tip

Exponent reminder: x⋅x2=x1+2=x3x\cdot x^2 = x^{1+2}=x^3. Add exponents when multiplying powers of the same base—do not multiply them.

Try it
Try it: distribute

Multiply 2a2b(3a−5b+ab2)2a^2b(3a - 5b + ab^2).

Show the answer

2a2b⋅3a=6a3b2a^2b \cdot 3a = 6a^3b; 2a2b⋅(−5b)=−10a2b22a^2b \cdot (-5b) = -10a^2b^2; 2a2b⋅ab2=2a3b32a^2b \cdot ab^2 = 2a^3b^3. Result: 6a3b−10a2b2+2a3b36a^3b - 10a^2b^2 + 2a^3b^3.

Multiplying Two Binomials (FOIL)

Concept
FOIL

FOIL names the four products you make when multiplying two binomials:

F⏟FirstO⏟OuterI⏟InnerL⏟Last\underbrace{\text{F}}_{\text{First}}\quad \underbrace{\text{O}}_{\text{Outer}}\quad \underbrace{\text{I}}_{\text{Inner}}\quad \underbrace{\text{L}}_{\text{Last}}

Then combine the two middle (Outer ++ Inner) like terms.

FOIL is the distributive property used twice: (3x−4)(2x+5)=3x(2x+5)−4(2x+5)(3x - 4)(2x + 5) = 3x(2x + 5) - 4(2x + 5). The box shows why there are four products: each of the two terms in one factor meets each of the two terms in the other. FOIL is only a way to remember all four; for bigger products the box is safer.

Example
Example: (x+4)(x−1)(x+4)(x-1)
First: x⋅x=x2Outer: x⋅(−1)=−xInner: 4⋅x=4xLast: 4⋅(−1)=−4Add: x2−x+4x−4=x2+3x−4.\begin{aligned} \text{First: } & x\cdot x = x^2 \\ \text{Outer: } & x\cdot(-1) = -x \\ \text{Inner: } & 4\cdot x = 4x \\ \text{Last: } & 4\cdot(-1) = -4 \\[2pt] \text{Add: } & x^2 - x + 4x - 4 = x^2 + 3x - 4. \end{aligned}
Side note
Where it goes wrong

Multiplying only first and last terms: (x+4)(x−1)=x2−4(x + 4)(x - 1) = x^2 - 4. The outer and inner products, −x-x and 4x4x, are missing. The full product is x2+3x−4x^2 + 3x - 4; check with x=1x = 1: 5⋅0=05 \cdot 0 = 0 and 1+3−4=01 + 3 - 4 = 0.

Example
Example with coefficients: (3x−4)(2x+5)(3x-4)(2x+5)
2x+53x−46x²15x−8x−20
Four cells, four products: 6x2+15x−8x−20=6x2+7x−206x^2 + 15x - 8x - 20 = 6x^2 + 7x - 20.
F: 3x⋅2x=6x2O: 3x⋅5=15xI: −4⋅2x=−8xL: −4⋅5=−206x2+15x−8x−20=6x2+7x−20.\begin{aligned} \text{F: } & 3x\cdot 2x = 6x^2 \\ \text{O: } & 3x\cdot 5 = 15x \\ \text{I: } & -4\cdot 2x = -8x \\ \text{L: } & -4\cdot 5 = -20 \\[2pt] & 6x^2 + 15x - 8x - 20 = 6x^2 + 7x - 20. \end{aligned}
Tip

FOIL is just the distributive property twice. Every term in the first binomial multiplies every term in the second. That idea is what lets us multiply bigger polynomials next.

Try it
Try it: FOIL

Multiply (4x−3)(x+6)(4x - 3)(x + 6) and (2y+5)(3y−2)(2y + 5)(3y - 2).

Show the answer

(4x−3)(x+6)=4x2+24x−3x−18=4x2+21x−18(4x - 3)(x + 6) = 4x^2 + 24x - 3x - 18 = 4x^2 + 21x - 18. (2y+5)(3y−2)=6y2−4y+15y−10=6y2+11y−10(2y + 5)(3y - 2) = 6y^2 - 4y + 15y - 10 = 6y^2 + 11y - 10.

Multiplying a Binomial by a Trinomial

Concept
Distribute Each Term

Multiply each term of the binomial by each term of the trinomial (that is 2×3=62\times 3 = 6 small products), then combine like terms and write in standard form.

Every term of the first factor must meet every term of the second, so a 22-term times a 33-term product has 2×3=62 \times 3 = 6 pieces before combining, the counting principle in algebra. A box with 22 rows and 33 columns is a checklist that no product gets skipped.

Example
Example: (2x−1)(x2+3x−5)(2x-1)(x^2+3x-5)
x²+3x−52x−12x³6x²−10x−x²−3x+5
Six products; like terms sit on the diagonals.

Distribute 2x2x, then distribute −1-1:

2x(x2+3x−5)=2x3+6x2−10x−1(x2+3x−5)=−x2−3x+5Add: 2x3+(6x2−x2)+(−10x−3x)+5=2x3+5x2−13x+5.\begin{aligned} 2x(x^2+3x-5) &= 2x^3 + 6x^2 - 10x \\ -1(x^2+3x-5) &= -x^2 - 3x + 5 \\[2pt] \text{Add: } & 2x^3 + (6x^2-x^2) + (-10x-3x) + 5 \\ &= 2x^3 + 5x^2 - 13x + 5. \end{aligned}
Side note
Where it goes wrong

Stopping after the first row: (2x−1)(x2+3x−5)=2x3+6x2−10x(2x - 1)(x^2 + 3x - 5) = 2x^3 + 6x^2 - 10x. The −1-1 must multiply all three terms too, adding −x2−3x+5-x^2 - 3x + 5.

Tip

Stay organized. Line up like terms in columns as you go, and count your products—for a binomial times a trinomial you should form exactly six before combining.

Try it
Try it: six products

Multiply (x+2)(x2−2x+4)(x + 2)(x^2 - 2x + 4).

Show the answer

x⋅(x2−2x+4)=x3−2x2+4xx \cdot (x^2 - 2x + 4) = x^3 - 2x^2 + 4x and 2⋅(x2−2x+4)=2x2−4x+82 \cdot (x^2 - 2x + 4) = 2x^2 - 4x + 8. Add: the x2x^2 and xx terms cancel, leaving x3+8x^3 + 8. (This is the sum-of-cubes pattern.)

Special Products

Concept
Two Patterns Worth Memorizing
Difference of squares:(a+b)(a−b)=a2−b2Perfect-square trinomial:(a+b)2=a2+2ab+b2(a−b)2=a2−2ab+b2\begin{aligned} \textbf{Difference of squares:}\quad & (a+b)(a-b) = a^2 - b^2 \\ \textbf{Perfect-square trinomial:}\quad & (a+b)^2 = a^2 + 2ab + b^2 \\ & (a-b)^2 = a^2 - 2ab + b^2 \end{aligned}

These come straight from FOIL, but recognizing the pattern saves time.

Both patterns are FOIL with a shortcut built in. In (a+b)(a−b)(a + b)(a - b) the outer and inner products are −ab-ab and +ab+ab, which cancel, leaving a2−b2a^2 - b^2. In (a−b)2(a - b)^2 they are −ab-ab twice, giving the middle term −2ab-2ab. The picture shows the first: a square of side aa with a bb-square removed can be cut and rearranged into an (a+b)(a + b)-by-(a−b)(a - b) rectangle.

Example
Difference of squares: (2x+5)(2x−5)(2x+5)(2x-5)
a = 2xb²b = 5a² − b²a + bheight a − b(a + b)(a − b)
Remove the bb-square from the aa-square and the rest rearranges into (a+b)(a−b)(a + b)(a - b).

Here a=2xa=2x and b=5b=5, so a2−b2a^2-b^2:

(2x)2−(5)2=4x2−25.(2x)^2 - (5)^2 = 4x^2 - 25.

Check with FOIL: 4x2−10x+10x−25=4x2−254x^2 - 10x + 10x - 25 = 4x^2 - 25. The middle terms cancel.

Side note
Where it goes wrong

Squaring each term: (3x−4)2=9x2−16(3x - 4)^2 = 9x^2 - 16 or 9x2+169x^2 + 16. The square of a difference has a middle term: (3x)2−2(3x)(4)+42=9x2−24x+16(3x)^2 - 2(3x)(4) + 4^2 = 9x^2 - 24x + 16. Test x=1x = 1: (−1)2=1(-1)^2 = 1, and 9−24+16=19 - 24 + 16 = 1.

Example
Perfect square: (3x−4)2(3x-4)^2

Here a=3xa=3x and b=4b=4, so a2−2ab+b2a^2 - 2ab + b^2:

(3x)2−2(3x)(4)+(4)2=9x2−24x+16.\begin{aligned} (3x)^2 - 2(3x)(4) + (4)^2 &= 9x^2 - 24x + 16. \end{aligned}
Tip

Do NOT drop the middle term!   (a+b)2≠a2+b2(a+b)^2 \neq a^2 + b^2.

The correct expansion is (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2. For example, (x+3)2=x2+6x+9(x+3)^2 = x^2 + 6x + 9, not x2+9x^2+9. The 2ab2ab term is the one students forget most often.

Try it
Try it: patterns

Expand (5y+2)2(5y + 2)^2 and (x2+7)(x2−7)(x^2 + 7)(x^2 - 7) using the patterns.

Show the answer

(5y)2+2(5y)(2)+22=25y2+20y+4(5y)^2 + 2(5y)(2) + 2^2 = 25y^2 + 20y + 4. With a=x2a = x^2, b=7b = 7: a2−b2=x4−49a^2 - b^2 = x^4 - 49.

Going Deeper: Advanced Polynomials

Concept
The Binomial Theorem

FOIL and repeated distribution get slow for high powers. The Binomial Theorem expands (a+b)n(a+b)^n all at once:

(a+b)n=∑k=0n(nk) a n−kb k,(a+b)^n = \sum_{k=0}^{n} \binom{n}{k}\, a^{\,n-k} b^{\,k},

where the binomial coefficient (nk)=n!k! (n−k)!\binom{n}{k} = \dfrac{n!}{k!\,(n-k)!} counts the ways to choose kk of the nn factors that contribute a bb.

Reading the pattern for a fixed nn: the power of aa starts at nn and drops by one each term, the power of bb starts at 00 and rises by one, and the two exponents in every term add up to nn.

Reminder — The binomial theorem:  (x+y)n=∑k=0n(nk)x n−kyk(x+y)^{n}=\sum_{k=0}^{n}\binom{n}{k}x^{\,n-k}y^{k}
Concept
Pascal's Triangle

The coefficients (nk)\binom{n}{k} are exactly the rows of Pascal's triangle. Each entry is the sum of the two entries above it, and every row begins and ends with 11.

n=0:1n=1:11n=2:121n=3:1331n=4:14641\begin{array}{ccccccccc} n=0: & & & & 1 & & & & \\ n=1: & & & 1 & & 1 & & & \\ n=2: & & 1 & & 2 & & 1 & & \\ n=3: & 1 & & 3 & & 3 & & 1 & \\ n=4: 1 & & 4 & & 6 & & 4 & & 1 \end{array}

So (a+b)4=a4+4a3b+6a2b2+4ab3+b4(a+b)^4 = a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4: the row 1,4,6,4,11,4,6,4,1 becomes the coefficients directly.

Example
Example: Expand (2x+3)3(2x+3)^3 with the Binomial Theorem

Use row n=3n=3 of Pascal's triangle: 1,3,3,11,3,3,1. Take a=2xa=2x, b=3b=3:

(2x+3)3=1 (2x)3+3 (2x)2(3)+3 (2x)(3)2+1 (3)3=8x3+3(4x2)(3)+3(2x)(9)+27=8x3+36x2+54x+27.\begin{aligned} (2x+3)^3 &= 1\,(2x)^3 + 3\,(2x)^2(3) + 3\,(2x)(3)^2 + 1\,(3)^3 \\ &= 8x^3 + 3(4x^2)(3) + 3(2x)(9) + 27 \\ &= 8x^3 + 36x^2 + 54x + 27. \end{aligned}
Tip

The coefficient is not just the Pascal number. In (2x+3)3(2x+3)^3 each term also carries the powers of the constants 22 and 33. The Pascal entry 33 became 3636 once (2x)2(2x)^2 and 313^1 were multiplied in. Always raise both pieces of the binomial to their powers.

Concept
Extracting One Coefficient Without Full Expansion

Sometimes you only need a single coefficient of a product. Instead of multiplying everything out, collect only the pairs of terms whose degrees add up to the power you want.

To find the coefficient of xkx^k in a product, list every way to pick one term from each factor so their exponents sum to kk, multiply those coefficients, and add the results.

Example
Example: Coefficient of x2x^2 in (x2+3x−4)(2x2−x+5)(x^2+3x-4)(2x^2-x+5)

We need every pair of terms whose exponents add to 22:

x2⋅5=5x23x⋅(−x)=−3x2−4⋅2x2=−8x2Sum of coefficients: 5+(−3)+(−8)=−6.\begin{aligned} x^2 \cdot 5 &= 5x^2 \\ 3x \cdot (-x) &= -3x^2 \\ -4 \cdot 2x^2 &= -8x^2 \\[2pt] \text{Sum of coefficients: } & 5 + (-3) + (-8) = -6. \end{aligned}

So the coefficient of x2x^2 is −6-6, found without computing any other term.

Concept
Recovering a2+b2a^2+b^2 and a3+b3a^3+b^3 from a+ba+b and abab

The sum a+ba+b and product abab contain enough information to rebuild higher symmetric expressions. Starting from (a+b)2=a2+2ab+b2(a+b)^2 = a^2+2ab+b^2 and (a+b)3=a3+3a2b+3ab2+b3(a+b)^3 = a^3+3a^2b+3ab^2+b^3, rearrange:

a2+b2=(a+b)2−2ab,a3+b3=(a+b)3−3ab(a+b).\begin{aligned} a^2+b^2 &= (a+b)^2 - 2ab, \\ a^3+b^3 &= (a+b)^3 - 3ab(a+b). \end{aligned}

The second identity also factors as a3+b3=(a+b)(a2−ab+b2)a^3+b^3=(a+b)(a^2-ab+b^2); both give the same value.

Example
Example: If a+b=5a+b=5 and ab=6ab=6, find a2+b2a^2+b^2 and a3+b3a^3+b^3

Substitute directly into the identities:

a2+b2=(a+b)2−2ab=52−2(6)=25−12=13,a3+b3=(a+b)3−3ab(a+b)=53−3(6)(5)=125−90=35.\begin{aligned} a^2+b^2 &= (a+b)^2 - 2ab = 5^2 - 2(6) = 25 - 12 = 13, \\ a^3+b^3 &= (a+b)^3 - 3ab(a+b) = 5^3 - 3(6)(5) = 125 - 90 = 35. \end{aligned}

(Check: a=2,b=3a=2,b=3 give a+b=5a+b=5, ab=6ab=6, and indeed 4+9=134+9=13, 8+27=358+27=35.)

Concept
Extending the Special Products: (a+b+c)2(a+b+c)^2

The perfect-square pattern generalizes to three terms. Every term squares, and every distinct pair produces a doubled cross term:

(a+b+c)2=a2+b2+c2+2ab+2ac+2bc.(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc.

There are three squares and three cross terms because there are three ways to pair up aa, bb, and cc.

Tip

Count the cross terms. A common error is writing only a2+b2+c2a^2+b^2+c^2. With nn terms there are nn squares plus one doubled cross term for each pair. For example, (x+2+3y)2=x2+4+9y2+4x+6xy+12y(x+2+3y)^2 = x^2 + 4 + 9y^2 + 4x + 6xy + 12y.

Concept
End Behavior from the Leading Term

For large ∣x∣|x|, a polynomial behaves like its leading term alone—the highest-degree term dominates every other. So the degree and the sign of the leading coefficient decide the end behavior:

  • Even degree: both ends point the same way—up/up if the leading coefficient is positive, down/down if negative.
  • Odd degree: the ends point opposite ways—down/up if positive, up/down if negative.
Example
Example: End behavior of −2x3+40x2−7-2x^3 + 40x^2 - 7
xy
Up on the left, down on the right: the −2x3-2x^3 term wins once x>20x > 20.

Ignore all but the leading term −2x3-2x^3. The degree is odd (33) and the leading coefficient is negative (−2-2), so the ends point opposite ways: as x→+∞x\to+\infty the value →−∞\to-\infty, and as x→−∞x\to-\infty the value →+∞\to+\infty (up on the left, down on the right). The large +40x2+40x^2 term changes the middle shape but never the ends.

Concept
Polynomial Long Division (Preview)

When a polynomial does not divide evenly, long division splits it into a quotient plus a remainder, mirroring long division of numbers. At each step: divide the leading term of the current dividend by the leading term of the divisor, multiply back, and subtract.

Example
Example: Divide x2+5x+7x^2+5x+7 by x+2x+2
x2÷x=x,andx(x+2)=x2+2x,(x2+5x+7)−(x2+2x)=3x+7,3x÷x=3,and3(x+2)=3x+6,(3x+7)−(3x+6)=1  (remainder).\begin{aligned} x^2 \div x &= x, \quad\text{and}\quad x(x+2) = x^2+2x, \\ (x^2+5x+7) - (x^2+2x) &= 3x+7, \\ 3x \div x &= 3, \quad\text{and}\quad 3(x+2) = 3x+6, \\ (3x+7) - (3x+6) &= 1 \ \ (\text{remainder}). \end{aligned}

So x2+5x+7=(x+2)(x+3)+1x^2+5x+7 = (x+2)(x+3) + 1, i.e. the quotient is x+3x+3 with remainder 11.

Tip

Keep everything in standard form and hold placeholders. Before dividing, order both polynomials by descending degree and insert 00 coefficients for any missing powers (e.g. write x3+1x^3+1 as x3+0x2+0x+1x^3+0x^2+0x+1) so like terms line up during each subtraction.

Why It Works

Multiplying polynomials is the distributive property applied repeatedly: (a+b)(c+d)=a(c+d)+b(c+d)=ac+ad+bc+bd(a + b)(c + d) = a(c + d) + b(c + d) = ac + ad + bc + bd. The area model makes it geometric — a rectangle with sides a+ba + b and c+dc + d contains four sub-rectangles, one per product. Special products like (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2 are pictures of a square cut into a square, two equal rectangles, and a smaller square.

Tip
Reading a proof

Do not read a proof the way you read a rule. Cover the last line, ask what the previous line forces, and only then uncover it. If a step feels like magic, that is the step to work by hand with a concrete number.

Formulas, Proofs & Tips

Tip
The distributive property
a(b+c)=ab+aca(b+c)=ab+ac

What it means. Multiplying a sum multiplies each piece of it.

Example. 3(x+2)=3x+63(x+2)=3x+6.

Why it works. a(b+c)a(b+c) is b+cb+c added aa times. Regrouping those copies gives bb added aa times plus cc added aa times, i.e. ab+acab+ac. It is also the area of an a×(b+c)a\times(b+c) rectangle split into two.

Tip. Distribute the sign too: −(x−4)=−x+4-(x-4)=-x+4. Run it backwards to factor.

Tip
Degree and end behaviour
deg⁡(fg)=deg⁡f+deg⁡g;leading term controls the ends\deg(fg)=\deg f+\deg g;\qquad \text{leading term controls the ends}

What it means. The highest-power term decides what the graph does far left and far right.

Example. −2x3+⋯-2x^3+\cdots rises to the left and falls to the right (odd degree, negative lead).

Why it works. For very large ∣x∣|x|, xnx^{n} dwarfs every lower power, so the leading term dominates the sum. Multiplying polynomials multiplies their leading terms, adding the exponents.

Tip. Even degree: both ends go the same way. Odd degree: opposite ways. A positive leading coefficient sends the right end up.