Course Review

Study Sheet

Course Review

Every definition, rule, and formula for the whole course --- all 11 topics in one place

Foundations

Concept
Real Number Families

Every number in Algebra 1 is a real number, sorted into nested sets:

  • Natural: 1,2,3,1, 2, 3, \dotsWhole: 0,1,2,3,0, 1, 2, 3, \dots
  • Integers: ,2,1,0,1,2,\dots, -2, -1, 0, 1, 2, \dots
  • Rational: any ab\frac{a}{b} with integers a,ba,b and b0b \ne 0; decimals end or repeat.
  • Irrational: cannot be written as a fraction; decimals never end and never repeat (e.g. 2, π\sqrt{2},\ \pi).

Each set sits inside the next: naturals \subset wholes \subset integers \subset rationals.

Concept
Order of Operations (PEMDAS)
  • P --- Parentheses / grouping (also |\,\cdot\,| and fraction bars)
  • E --- Exponents
  • MD --- Multiply and Divide, left to right
  • AS --- Add and Subtract, left to right

Multiplication and division are equal in rank; do whichever comes first left to right. Same for addition and subtraction.

Concept
Properties & Like Terms

multicols2

  • Commutative: a+b=b+aa+b=b+a,  ab=ba\ ab=ba
  • Associative: (a+b)+c=a+(b+c)(a+b)+c=a+(b+c)
  • Distributive: a(b+c)=ab+aca(b+c)=ab+ac
  • Identity: a+0=aa+0=a,  a1=a\ a\cdot 1=a

multicols Like terms share the same variable part (same letters, same exponents). Combine by adding coefficients: 5x+3x=8x5x+3x=8x. Note x2x^2 and xx are not like terms.

Example
Evaluate by substitution

Evaluate   3x22y\;3x^2 - 2y when x=2x=-2, y=5y=5.

3x22y=3(2)22(5)=3(4)10=1210=2.\begin{aligned} 3x^2 - 2y &= 3(-2)^2 - 2(5) \\ &= 3(4) - 10 = 12 - 10 = 2. \end{aligned}
Tip

Wrap every substituted value in parentheses: (2)2=4(-2)^2 = 4, but 22=4-2^2 = -4. The exponent applies only to what it touches.

Solving Equations & Inequalities

Concept
Multi-Step Equations

Goal: isolate the variable. Work backwards through PEMDAS.

  • Distribute and clear parentheses; clear fractions by multiplying by the LCD.
  • Combine like terms on each side.
  • Move variable terms to one side, constants to the other (do the same to both sides).
  • Divide by the coefficient.

Variables on both sides: collect all variable terms on the side that keeps the coefficient positive.

Concept
Literal Equations & Solution Counts

Literal equation: solve for one letter in terms of the others using the same isolation steps. Example: A=12bhh=2AbA = \tfrac{1}{2}bh \Rightarrow h = \dfrac{2A}{b}.

How many solutions?

  • Variable remains, e.g. x=4x = 4 \Rightarrow one solution.
  • True statement, e.g. 6=66 = 6 \Rightarrow all real numbers (identity).
  • False statement, e.g. 3=73 = 7 \Rightarrow no solution.
Concept
Inequalities, Compound & Absolute Value

Solve inequalities like equations, with one rule: multiplying or dividing by a negative flips the inequality sign.

Compound: “AND” means both true (overlap, a<x<ba < x < b); “OR” means either true (union).

Absolute value (for k>0k>0):

x<k  k<x<k(AND)x>k  x<k  or  x>k(OR)\begin{aligned} |x| < k \ &\Rightarrow\ -k < x < k &&(\text{AND}) \\ |x| > k \ &\Rightarrow\ x < -k \ \text{ or } \ x > k &&(\text{OR}) \end{aligned}
Example
Solve a multi-step equation

Solve   3(x4)=5x+2\;3(x - 4) = 5x + 2.

3x12=5x+2distribute122=5x3xcollect terms14=2x  x=7.\begin{aligned} 3x - 12 &= 5x + 2 && \text{distribute} \\ -12 - 2 &= 5x - 3x && \text{collect terms} \\ -14 &= 2x \ \Rightarrow\ x = -7. \end{aligned}
Tip

Only flip the inequality sign when you multiply or divide by a negative --- not when a negative simply appears. 2x<6x>3-2x < 6 \Rightarrow x > -3.

Linear Equations & Functions

Concept
Slope

Slope mm measures steepness (rise over run):

m=y2y1x2x1=riserun.m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{\text{rise}}{\text{run}}.

Positive mm rises left-to-right; negative mm falls. Horizontal lines have m=0m=0; vertical lines have undefined slope.

Concept
Forms of a Linear Equation
  • Slope-intercept: y=mx+by = mx + b  (mm slope, bb is yy-intercept)
  • Point-slope: yy1=m(xx1)y - y_1 = m(x - x_1)
  • Standard: Ax+By=CAx + By = C  (A,B,CA, B, C integers, A0A \ge 0)

Intercepts: set y=0y=0 for the xx-intercept, set x=0x=0 for the yy-intercept.

Concept
Parallel, Perpendicular & Function Notation
  • Parallel lines have equal slopes: m1=m2m_1 = m_2.
  • Perpendicular lines have opposite reciprocal slopes: m1m2=1m_1 \cdot m_2 = -1, so m2=1m1m_2 = -\dfrac{1}{m_1}.

Function notation: f(x)f(x) names the output for input xx. A relation is a function if each input has exactly one output (passes the vertical line test). f(3)f(3) means substitute 33 for xx.

Example
Equation through two points

Line through (1,2)(1, 2) and (3,8)(3, 8).

m=8231=62=3,y2=3(x1)  y=3x1.\begin{aligned} m &= \frac{8 - 2}{3 - 1} = \frac{6}{2} = 3, \\ y - 2 &= 3(x - 1) \ \Rightarrow\ y = 3x - 1. \end{aligned}
Tip

A line perpendicular to y=2x+5y = 2x + 5 has slope 12-\tfrac{1}{2}: flip the fraction and change the sign.

Systems of Equations & Inequalities

Concept
Three Solution Methods

A solution (x,y)(x,y) satisfies both equations --- the point where the graphs cross.

  • Graphing: plot both lines; the intersection is the solution.
  • Substitution: solve one equation for a variable, plug into the other. Best when a variable is already isolated.
  • Elimination: add or subtract equations (scale first) to cancel one variable. Best when lined up in standard form.
Concept
Number of Solutions
  • One solution: lines cross once (different slopes).
  • No solution: parallel lines, same slope, different intercept (variables cancel, false statement).
  • Infinitely many: same line (variables cancel, true statement).

Systems of inequalities: graph each, shade; the solution is the overlap of shaded regions.

Example
Solve by elimination

Solve   2x+3y=12\;2x + 3y = 12 and   2xy=4\;2x - y = 4.

(2x+3y)(2xy)=1244y=8  y=2,2x2=4  x=3.\begin{aligned} (2x+3y)-(2x-y) &= 12 - 4 \\ 4y &= 8 \ \Rightarrow\ y = 2, \\ 2x - 2 &= 4 \ \Rightarrow\ x = 3. \end{aligned}

Solution: (3,2)(3, 2).

Tip

Always check your answer in both original equations --- a point that fits only one equation is not a solution to the system.

Exponents & Exponent Rules

Concept
The Exponent Rules

For any nonzero base: multicols2

  • Product: xaxb=xa+bx^a \cdot x^b = x^{a+b}
  • Quotient: xaxb=xab\dfrac{x^a}{x^b} = x^{a-b}
  • Power of power: (xa)b=xab(x^a)^b = x^{ab}
  • Power of product: (xy)a=xaya(xy)^a = x^a y^a
  • Power of quotient: (xy)a=xaya\left(\dfrac{x}{y}\right)^a = \dfrac{x^a}{y^a}
  • Zero: x0=1x^0 = 1

multicols Negative exponent: xa=1xax^{-a} = \dfrac{1}{x^a} --- move the factor across the fraction bar to make the exponent positive.

Concept
Scientific Notation

A number written as a×10na \times 10^n where 1a<101 \le a < 10 and nn is an integer.

  • Large numbers: positive nn.   5,200,000=5.2×106\;5{,}200{,}000 = 5.2 \times 10^6.
  • Small numbers: negative nn.   0.00047=4.7×104\;0.00047 = 4.7 \times 10^{-4}.

Multiply/divide by combining the aa values and adding/subtracting the exponents.

Example
Simplify with exponent rules

Simplify   6x5y22x2y5\;\dfrac{6x^5 y^2}{2x^2 y^5}.

6x5y22x2y5=3x52y25=3x3y3=3x3y3.\begin{aligned} \frac{6x^5 y^2}{2x^2 y^5} &= 3x^{5-2} y^{2-5} = 3x^3 y^{-3} = \frac{3x^3}{y^3}. \end{aligned}
Tip

x0=1x^0 = 1, not 00. And a negative exponent never makes a number negative --- it makes a reciprocal: 23=182^{-3} = \tfrac{1}{8}.

Polynomials

Concept
Vocabulary & Add/Subtract

A polynomial is a sum of terms axnax^n (whole-number exponents). Degree is the highest exponent; name by terms: monomial (1), binomial (2), trinomial (3).

Add/Subtract: combine like terms. To subtract, distribute the minus sign to every term in the second polynomial first.

Concept
Multiplying & Special Products

FOIL for two binomials --- First, Outer, Inner, Last:

(a+b)(c+d)=ac+ad+bc+bd.(a+b)(c+d) = ac + ad + bc + bd.

Special products (memorize):

(a+b)2=a2+2ab+b2(ab)2=a22ab+b2(a+b)(ab)=a2b2\begin{aligned} (a+b)^2 &= a^2 + 2ab + b^2 \\ (a-b)^2 &= a^2 - 2ab + b^2 \\ (a+b)(a-b) &= a^2 - b^2 \end{aligned}
Example
Multiply two binomials

Expand   (2x+3)(x5)\;(2x + 3)(x - 5).

(2x+3)(x5)=2x210x+3x15=2x27x15.\begin{aligned} (2x+3)(x-5) &= 2x^2 - 10x + 3x - 15 \\ &= 2x^2 - 7x - 15. \end{aligned}
Tip

(a+b)2a2+b2(a+b)^2 \ne a^2 + b^2. The middle term 2ab2ab is real: (x+4)2=x2+8x+16(x+4)^2 = x^2 + 8x + 16.

Factoring

Concept
Factoring Strategy (in order)
  • GCF first, always: pull out the greatest common factor.   6x2+9x=3x(2x+3)\;6x^2 + 9x = 3x(2x + 3).
  • Difference of squares: a2b2=(a+b)(ab)a^2 - b^2 = (a+b)(a-b).
  • Perfect-square trinomial: a2±2ab+b2=(a±b)2a^2 \pm 2ab + b^2 = (a \pm b)^2.
  • Trinomial x2+bx+cx^2 + bx + c: find two numbers that multiply to cc and add to bb.
  • Leading coefficient 1\ne 1: factor by grouping (AC method).
Concept
Zero Product Property

If a product equals zero, at least one factor is zero:

if (xr)(xs)=0, then x=r or x=s.\text{if } (x - r)(x - s) = 0, \text{ then } x = r \text{ or } x = s.

This turns a factored equation into solutions (the roots).

Example
Factor a trinomial

Factor   x22x15\;x^2 - 2x - 15.

Two numbers: multiply to 15, add to 25,+3.x22x15=(x5)(x+3).\begin{aligned} &\text{Two numbers: multiply to } -15,\ \text{add to } -2 \Rightarrow -5, +3. \\ &x^2 - 2x - 15 = (x - 5)(x + 3). \end{aligned}
Tip

a2+b2a^2 + b^2 (a sum of squares) does not factor over the real numbers. Only the difference of squares factors.

Quadratic Functions

Concept
Graph of y=ax2+bx+cy = ax^2 + bx + c

The graph is a parabola. It opens up if a>0a > 0, down if a<0a < 0.

  • Axis of symmetry / vertex xx:  x=b2a\ x = -\dfrac{b}{2a}.
  • Vertex: (b2a, f ⁣(b2a))\left(-\dfrac{b}{2a},\ f\!\left(-\dfrac{b}{2a}\right)\right) --- the minimum or maximum point.
  • Vertex form: y=a(xh)2+ky = a(x - h)^2 + k with vertex (h,k)(h, k).
Concept
Ways to Solve a Quadratic
  • Factoring: write as a product =0=0, use zero product property.
  • Square roots: for x2=kx^2 = k, then x=±kx = \pm\sqrt{k}.
  • Completing the square: add (b2)2\left(\dfrac{b}{2}\right)^2 to form a perfect square.
  • Quadratic formula (always works):
x=b±b24ac2a.x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.
Reminder — The quadratic formula:x=b±b24ac2a(a0)x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\qquad (a\neq 0)
Concept
The Discriminant

The discriminant is   D=b24ac\;D = b^2 - 4ac (under the radical). It counts real solutions:

  • D>0D > 0: two real solutions.
  • D=0D = 0: one (repeated) real solution.
  • D<0D < 0: no real solutions.
Example
Quadratic formula

Solve   x2+3x10=0\;x^2 + 3x - 10 = 0  (a=1, b=3, c=10a=1,\ b=3,\ c=-10).

x=3±324(1)(10)2(1)=3±492=3±72  x=2  or  x=5.\begin{aligned} x &= \frac{-3 \pm \sqrt{3^2 - 4(1)(-10)}}{2(1)} = \frac{-3 \pm \sqrt{49}}{2} \\ &= \frac{-3 \pm 7}{2} \ \Rightarrow\ x = 2 \ \text{ or } \ x = -5. \end{aligned}
Tip

Set the equation equal to 00 before reading off aa, bb, cc. Keep the sign attached to each: in x24x=5x^2 - 4x = 5, rewrite as x24x5=0x^2 - 4x - 5 = 0 so c=5c = -5.

Radicals

Concept
Simplifying & Operating

A radical is simplified when no perfect-square factor remains under the root.

ab=ab,ab=ab.\sqrt{ab} = \sqrt{a}\,\sqrt{b}, \qquad \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}.

Example: 50=252=52\sqrt{50} = \sqrt{25 \cdot 2} = 5\sqrt{2}.

Add/Subtract: only combine like radicals (same radicand): 23+53=732\sqrt{3} + 5\sqrt{3} = 7\sqrt{3}.

Multiply: ab=ab\sqrt{a}\cdot\sqrt{b} = \sqrt{ab}.

Concept
Rationalizing & Pythagorean Theorem

Rationalize a denominator by removing the root from the bottom:

12=1222=22.\frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}}\cdot\frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}.

Pythagorean theorem (right triangles, legs a,ba,b, hypotenuse cc):

a2+b2=c2.a^2 + b^2 = c^2.
Reminder — The Pythagorean theorem:a2+b2=c2a^2+b^2=c^2
Example
Find the hypotenuse

Legs 66 and 88.

c2=62+82=36+64=100c=100=10.\begin{aligned} c^2 &= 6^2 + 8^2 = 36 + 64 = 100 \\ c &= \sqrt{100} = 10. \end{aligned}
Tip

a+ba+b\sqrt{a+b} \ne \sqrt{a} + \sqrt{b}. For instance 9+16=25=5\sqrt{9+16} = \sqrt{25} = 5, but 9+16=3+4=7\sqrt{9} + \sqrt{16} = 3 + 4 = 7.

Rational Expressions

Concept
Simplify & Excluded Values

A rational expression is a fraction of polynomials. Factor top and bottom, then cancel common factors.

x29x2+4x+3=(x3)(x+3)(x+1)(x+3)=x3x+1.\frac{x^2 - 9}{x^2 + 4x + 3} = \frac{(x-3)(x+3)}{(x+1)(x+3)} = \frac{x-3}{x+1}.

Excluded values: any xx making an original denominator 00 is not allowed (here x1x \ne -1 and x3x \ne -3).

Concept
Operations & Solving
  • Multiply: factor, cancel, multiply across.
  • Divide: multiply by the reciprocal of the second fraction.
  • Add/Subtract: rewrite over a common denominator (LCD), combine numerators.
  • Solve rational equations: multiply every term by the LCD to clear fractions, solve, then discard any answer that is an excluded value.
Example
Cancel only common factors

Simplify   x2+5x+6x+2\;\dfrac{x^2 + 5x + 6}{x + 2}.

x2+5x+6x+2=(x+2)(x+3)x+2=x+3,x2.\begin{aligned} \frac{x^2 + 5x + 6}{x+2} &= \frac{(x+2)(x+3)}{x+2} = x + 3, \quad x \ne -2. \end{aligned}
Tip

Cancel factors, never terms. You may not cancel the xx in x+3x\dfrac{x+3}{x}, because x+3x+3 is a sum, not a product.

Data & Statistics

Concept
Center: Mean, Median, Mode
  • Mean (average):  sum of valuesnumber of values\ \dfrac{\text{sum of values}}{\text{number of values}}.
  • Median: middle value of the ordered list (average the two middle values if the count is even).
  • Mode: the value(s) that appear most often.

The median resists outliers (extreme values); the mean gets pulled toward them.

Concept
Spread: Range & IQR
  • Range == maximum - minimum.
  • Quartiles: Q1Q_1 (median of lower half), Q2Q_2 (median), Q3Q_3 (median of upper half).
  • Interquartile range:  IQR=Q3Q1\ \text{IQR} = Q_3 - Q_1 --- the spread of the middle 50%50\%.
Concept
Scatter Plots & Line of Best Fit

A scatter plot shows paired data to reveal a relationship (correlation):

  • Positive: both rise together.  Negative: one rises as the other falls.
  • No correlation: no clear pattern.

The line of best fit models the trend; use its equation y=mx+by = mx + b to predict values. Correlation does not prove causation.

Example
Mean and median

Data:   4,7,7,9,13\;4, 7, 7, 9, 13.

Mean=4+7+7+9+135=405=8,Median=7 (middle),Mode=7.\begin{aligned} \text{Mean} &= \frac{4+7+7+9+13}{5} = \frac{40}{5} = 8, \\ \text{Median} &= 7 \ (\text{middle}), \qquad \text{Mode} = 7. \end{aligned}
Tip

Always order the data before finding the median or quartiles. The mode is the most frequent value, not the largest.